Answer: 44.37 degrees C
Explanation:
Use combined gas law: (P1)(V1)/T1=(P2)(V2)/T2
For most gas laws, you must convert to Kelvin:
K=deg C+273
K=25+273=298 K
Plug and chug:
(1.0 atm)(1.2 L)/(298 K)=(0.71 atm)(1.8 L)/(x)
Solve for x and get 317.37 K
Subtract 273 from this to convert to degrees Celsius. You will get 44.37 degrees Celsius.
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1-Bromobutane reacts with water to form 1-butanol according to the following equation overall rate law for this proposed mechanism is rate = k [C₄H₉Br]
The reaction intermediate in the chemical species that is formed in one elementary step and consumed in subsequent step and the slowest step in the reaction mechanism is rate determining step and the rate determining step limit the overall rate and therefore determines the rate law for the overall reaction
Here given reaction
C₄H₉Br(aq) + 2H₂O(l) → C₄H₉OH(aq) + H₃O⁺(aq) + Br⁻(aq)
And the following is a proposed mechanism for the reaction
C₄H₉Br(aq) → C₄H₉⁺(aq) + Br⁻(aq) slow
C₄H₉⁺(aq) + H₂O(l) → C₄H₉OH₂⁺(aq) fast
C₄H₉OH₂⁺(aq) + H₂O(l) → C₄H₉OH(aq) + H₃O⁺(aq) fast
So in that 1st step is the rate determining step means slow step
So rate expressions take the general form: rate = k . [A]a . [B]b
So given equation rate expressions is k [C₄H₉Br]
Know more about rate expression
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Answer: any answer choices
Explanation:
Answer:
B) 6
Explanation:
Methylcyclopentane consist of 3 types of hydrogen which are 1° (primary), 2° (secondary) and 3° (tertiary) hydrogen atoms. In the chlorination of methylcyclopentane, there are four monochlorinated products possible and two stereoisomers.
Answer:- Van't hoff factor(i) for the unknown ionic compound is 2.77.
Solution:- Elevation in boiling point is a colligative property and the equation used for solving this type of problems is...
delta Tb = i x m x kb
where delt Tb is elevation in boiling point.
i is Von't hoff factor.
m is molality of the solution and kb is the molal elevation constant. It's value for water is 0.512.
Boiling point of solution is given as 103.4 degree C and we know that water boils at 100 degree C.
So, delta Tb = 103.4 - 100 = 3.4 degree C
molality is given as 2.4m.
Let's plug in the values...
3.4 = i x 2.4 x 0.512
i = 3.4/(2.4 x 0.512)
i = 2.77