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Minchanka [31]
3 years ago
9

The sum of three distinct primes is 20. What is their largest possible product?

Mathematics
1 answer:
ehidna [41]3 years ago
5 0

Answer:

154

Step-by-step explanation:

Primes less than 20 are:

2, 3, 5, 7, 11, 13, 17, 19

Possible combinations that add up to 20 are:

2 + 5 + 13

2 + 7 + 11

The products are:

2 × 5 × 13 = 130

2 × 7 × 11 = 154

So the largest possible product is 154.

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A number, y, is equal to twice the sum of a smaller number and 3. The larger number is also equal to 5 more than 3 times the sma
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Answer:

The equations represent the situation is y=2x+6 and y=5+3x.

Step-by-step explanation:

Consider the provided information.

First convert the statement into mathematical representation.

Consider the smaller number is <em>x</em> and the larger number is <em>y</em>.

<em>y</em>, is equal to twice the sum of a smaller number and 3.    

This information can be written as: y=2(x+3)

Which can be further solve as:

y=2x+6

The larger number is also equal to 5 more than 3 times the smaller number.

This information can be written as: y=5+3x

Thus, the equations represent the situation is y=2x+6 and y=5+3x.

Which can be further solve as:

2x+6=5+3x

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Now, substitute the value of <em>x</em> in y=5+3x.

y=5+3

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