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sergejj [24]
1 year ago
9

Identify the independent and dependent quantities and their units.David rode his bike to the park. After staying at the park for

a while, he continued his ride to thegrocery store. The graph shown represents this situation.
Mathematics
1 answer:
Nitella [24]1 year ago
3 0

when the time is between 0 and 15 minutes, the distance depends on the time on a relation: d =(1/10)t

when the time is between 15 and 40 minutes, the distance is independent of the time, it is fixed d = 1.5 miles

when the time is between 40 and 50 minutes, the distance depends on the time on the relation: d = 1.5 + (1/10)(t - 40)

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Pls answer correctly thnks
hammer [34]

-5x+3y = 10~~~~ .....(i)\\\\2x+5y =-35~~~ ....(ii)\\\\\text{Multiply equation (ii) by}~ \dfrac 35~ \text{ and do  (ii) -(i)}\\\\\\\dfrac 35(2x+5y) - (-5x+3y) = \dfrac 35}(-35) - 10\\\\\implies \dfrac{6x}5 +3y + 5x -3y = -21-10  = -31\\\\\implies \dfrac{6x + 25x}5  = -31\\\\\implies 31x = -31 \times 5\\\\\implies x = -5\\\\\text{Substitute }~x=-5~ \text{in equation (ii):}\\\\2(-5) +5y =-35\\\\\implies -10 +5y = -35\\\\\implies 5y = -35 +10 = -25\\\\\implies y = - \dfrac{25}5 = -5

\text{Hence,}~ \textbf{(x,y) = (-5, -5)}

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