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MAVERICK [17]
3 years ago
6

Edgar is learning to make handmade corn tortillas from his grandmother in preparation for a family gathering. His

Mathematics
1 answer:
Tomtit [17]3 years ago
4 0
To make 90 tortillas, he needs to make 6 batches. 6*15=90
2 cups masa per batch ->. 2 * 6=12 cups Masa
1.5 water per batch -> 1.5. * 6= 9 cups water
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2. a. The center for research in data science has a vacancy of 5 interns under a research attachment program. However, 20 studen
Yuliya22 [10]

Answer:  15504

Step-by-step explanation:

Given : The center for research in data science has a vacancy of 5 interns under a research attachment program.

Number of students applied = 20

The combination of n people taking r at a time is given by :-

C(n,r)=\dfrac{n!}{r!(n-r)!}

Since, all students fulfill the minimum CGPA criteria it means all 20 students are equally eligible.

Then , the number of ways to select a team of 5 interns from all 20 interns :-

C(20,5)=\dfrac{20!}{5!(20-5)!}\\\\=\dfrac{20\times19\times18\times17\times16\times15!}{5!15!}\\\\=15504

Hence, the number of ways to select a team of 5 interns. =  

7 0
4 years ago
HEY CAN YALL PLS ANSWER DIS RQ
Fittoniya [83]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A 6 foot tall football player casts a 16 inch shadow at the same time the stadium bleachers cast a 6 foot shadow how tall are th
Tom [10]
I believe its 27.75. I wouldn't take my word for it though.
7 0
3 years ago
Read 2 more answers
Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
3 years ago
Find the solution to the system of equations. 4x + 3y = –1 3x – 9y = 33
alexandr1967 [171]

Answer:

Step-by-step explanation:

4x + 3y = -1         --------------(i)

3x - 9y = 33        -------------(ii)

multiply equation (i) by 3

(i)* 3     12x + 9y = -3

(ii)       <u>   3x - 9y = 33</u>

add,       15x = 30

                 x = 30/15

                 x = 2

Put x =2 in Equation (i)

4*2 + 3y = -1

8 +3y = -1

     3y = -1-8

     3y = -9

       y = -9/3

       y= -3

5 0
3 years ago
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