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algol [13]
2 years ago
8

!!!QUESTION ON PIC!!!

Mathematics
2 answers:
Sever21 [200]2 years ago
7 0

Answer:

I think that the rectangles,L's and I'm not sure about the other ones

muminat2 years ago
4 0
Squares, L’s upside down, and the triangles.

I am 100% sure those are congruent. The have the same shape, side lengths, and size.

Hope that helps!
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A five digit number is rounded to the 10000 place. Is it possible for the rounded number to be a six digit number? What would be
Alexxx [7]
Yes, it's possible for the rounded number to have six digits. For example - if you round 99999 to the 10000 place then you'll get 100000, which is a 6-digit number :)
5 0
4 years ago
What is the median of the data below?<br><br> 45, 19, 23, 67, 28, 35, 46, 21, 58, 60, 23, 51
VLD [36.1K]
To find the median, you will need to list the data from least to greatest and find the middle number.

19, 21, 23, 23, 28, 35, 45, 46, 51, 58, 60, 67

Cross out a number on both sides until you reach the middle number. In this case, we are left with 2 numbers that are in the middle since there is an even amount of numbers. 

When you reach the time where you have two middle numbers, we have to find the average of those two numbers. Our two middle numbers are 35 and 45. Since we have to find the average of those two numbers, we can add them. (35 + 45 = 80). Now, since we have two middle numbers, we have to divide them by 2. 
80 \div 2 = 40

Answer: \fbox {Median = 40}
4 0
3 years ago
Read 2 more answers
Find the Equation of a line that passes through the ordered pairs (-1, 7) and (8, -2).
kondaur [170]
The equation would be y=-x +6
5 0
3 years ago
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Question for the people out there hungry for brainliest and points.
svetlana [45]
Positive 3. Absolute values are never negative, they are either 0 or a positive. so -3 would be +3
6 0
3 years ago
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Which ordered pair is a solution to the system of equations y=x+3 and y=x^2-x
Elenna [48]

For this case we have the following system of equations:

y = x + 3\\y = x ^ 2-x

Equating the equations we have:

x ^ 2-x = x + 3\\x ^ 2-x-x-3 = 0\\x ^ 2-2x-3 = 0

To find the solutions we factor the equation. To do this, we look for two numbers that, when multiplied, result in -3 and when added, result in -2.

These numbers are: -3 and +1

-3 + 1 = -2\\-3 * (+ 1) = - 3

Thus, the factored equation is:

(x-3) (x + 1) = 0

Then, the solutions for the variable "x" are:

x_ {1} = 3\\x_ {2} = - 1

We find the solutions for the variable "y":

y_ {1} = x_ {1} + 3 = 3 + 3 = 6\\y_ {2} = x_ {2} + 3 = -1 + 3 = 2

Thus, the solutions are:

(x_ {1}, y_ {1}): (3,6)\\(x_ {2}, y_ {2}): (-1,2)

ANswer:

(x_ {1}, y_ {1}): (3,6)\\(x_ {2}, y_ {2}): (-1,2)

3 0
4 years ago
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