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alexgriva [62]
4 years ago
15

A heavy object moving [E] collides with a much lighter object moving [W]. If the collision is completely inelastic, is it possib

le for both objects to be at rest after the collision? Explain.
Physics
1 answer:
Gekata [30.6K]4 years ago
5 0

It is possible for both objects to be resting and not paying attention to what's coming their way, and they will remain at rest because even their alarm can't wake them up.

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In what way could the endocrine system and the nervous system be considered relatives
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They work together to influence many aspects of human behavior such as growth, reproduction, and metabolism, and the endocrine system also lends and hand with emotions!
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3 years ago
Select the correct answer.
KIM [24]

Answer:

periods 3-5

Explanation:

If you know your periodic table well, this is simple. but to explain it, periods 3-5 have elements that have electrons that fill the s, p and d orbitals. if you do not know, the s orbital starts off with the first period and the second period until you get totto the right side which is where the o block starts. the block is all of the transition metals and they all fill the s and p or ital as well.

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3 years ago
The process by which wind removes surface materials is called
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The process by which wind removes surface materials is called deflation.

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3 years ago
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A uniform steel rod has mass 0.400 kg and length 50.0 cm and is horizontal. A uniform sphere with radius
Eddi Din [679]

Explanation:

Center of gravity , Let center of rod is origin

= \frac{(0.400*0)+(0.800*\frac{50}{2}+10)+ (0.200 *(-(25+5)) }{0.400+0.800+0.200}

=15.71cm from the center of rod

5 0
3 years ago
When a liquid is introduced into the air space between the lens and the plate in a Newton's-rings apparatus, the diameter of the
Leviafan [203]

Answer:

n_l=1.58

Explanation:

Newton's ring equation relates the initial and final diameter of the ring, to the index of refraction of the air and the index of refraction of the liquid between the lens and the plates, as follows:

n_ld_f^2=n_ad_i^2

Solving for :

n_l=n_a\frac{d_i^2}{d_f^2}\\

Recall that the refractive index of the air is 1. So, replacing the given diameters:

n_l=\frac{(1.52cm)^2}{(1.21cm)^2}\\\\n_l=1.58

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4 years ago
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