While breaking glass with sound is an interesting trick it really takes a lot of effort vibrations diminishes do you to energy being carried away by the sound waves.
D (it was produced by cyanobacteria)!!!
Answer:
it is safe to stand at the end of the table
Explanation:
For this exercise we use the rotational equilibrium condition
Στ = 0
W x₁ - w x₂ - w_table x₃ = 0
M x₁ - m x₂ - m_table x₃ = 0
where the mass of the large rock is M = 380 kg and its distance to the pivot point x₁ = 850 cm = 0.85m
the mass of the man is 62 kg and the distance
x₂ = 4.5 - 0.85
x₂ = 3.65 m
the mass of the table (m_table = 22 kg) is at its geometric center
x_{cm} = L/2 = 2.25 m
x₃ = 2.25 -0.85
x₃ = 1.4 m
let's look for the maximum mass of man
m_{maximum} =
let's calculate
m_{maximum} =
(380 0.85 - 22 1.4) / 3.65
m_{maximum} = 80 kg
we can see that the maximum mass that the board supports without turning is greater than the mass of man
m_{maximum}> m
consequently it is safe to stand at the end of the table
Grav. Potential at surface of the asteroid:
V = - G.Ma./ R
V = (-) 6.67^-11 x 4.0^20kg / 5.7^5m .. .. V = (-) 4.681 *10 ^5 J/kg
The GPE of the package on the asteroid = 9.0kg x (-) 4.681*10^5J/kg = (-) 4.21 ^5
J
This is the amount of energy required to come back the
package to infinity.
The total energy that needs to be transported to the package:
GPE + KE(for 187m/s)
Total energy required E = 4.21*10^5 + (½x 9.0kg x 168²) = 5.48 * 10^5 J
When the required energy is to be complete by releasing a compressed spring,
Elastic PE stored in spring = ½.ke² = 5.48 * 10^5 J where e = compression
distance
e = √ (2 x 5.48*10^5 / 2.1*10^5)
e = 2.28 m