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Elza [17]
3 years ago
10

A uniform steel rod has mass 0.400 kg and length 50.0 cm and is horizontal. A uniform sphere with radius

Physics
1 answer:
Eddi Din [679]3 years ago
5 0

Explanation:

Center of gravity , Let center of rod is origin

= \frac{(0.400*0)+(0.800*\frac{50}{2}+10)+ (0.200 *(-(25+5)) }{0.400+0.800+0.200}

=15.71cm from the center of rod

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Answer:

2 ans : the bell has 8550 J energy

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How many oxygen (O) atoms are in a molecule of SiO2?<br> O A. 1<br> OB. 3<br> C. 4<br> D. 2
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Water falls without splashing at a rate of 0.200 L/s from a height of 3.60 m into a 0.730 kg bucket on a scale. If the bucket is
dimaraw [331]

Answer:

15.106 N

Explanation:

From the given information,

The weight of the bucket can be calculated as:

W_b = m_bg =  \\ \\  W_b = (0.730 \  kg) ( 9.80 \ m/s^2) \\ \\ W_b = 7.154 \ N

The mass of the water accumulated in the bucket after 3.20s is:

m_w= (0.20 \ L/s) ( 3.20)s

m _w=0.64 \ kg

To determine the weight of the water accumulated in the bucket, we have:

W_w = m_w g

W_w = ( 0.64  \ kg )(9.80\  m  \  /s^2)

W_w = 6.272 \ N

For the speed of the water before hitting the bucket; we have:

v = \sqrt{2gh}

v = \sqrt{2*9.80 \ m/s^2 * 3.60 \ m}

v = 8.4 m/s

Now, the force required to stop the water later when it already hit the bucket is:

F = v ( \dfrac {dm}{dt} )

F = (8.4 \ m/s)( 0.200 \ L/s)

F = 1.68 N

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3 years ago
What is the gravitational potential energy of a 0.550-kg projectile flying with 335 m/s, 72 meters above the ground?
Fofino [41]

Answer:

GPE = 388.08 Joules.

Explanation:

Given the following data;

Mass = 0.550kg

Speed = 335 m/s

Height = 72 meters

We know that acceleration due to gravity, g is equal to 9.8 m/s²

To find the gravitational potential energy;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

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