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3 years ago

A uniform steel rod has mass 0.400 kg and length 50.0 cm and is horizontal. A uniform sphere with radius

Physics

1 answer:

Eddi Din [679]3 years ago

5 0

Explanation:

Center of gravity , Let center of rod is origin

= $\frac{(0.400*0)+(0.800*\frac{50}{2}+10)+ (0.200 *(-(25+5)) }{0.400+0.800+0.200}$

=15.71cm from the center of rod

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A certain spring has a stiffness of 50 N/m. A block of mass 2 kg is attached to the end of the spring. Find the damping coeffici

Monica [59]

Answer:

The damping coefficient is 20.

Explanation:

Given that,

Spring constant = 50 N/m

Mass of block = 2 kg

We need to calculate the damping coefficient

Using formula of damping coefficient

$b = 2\sqrt{km}$

$b=2\sqrt{50\times2}$

$b=20$

In case of critical damping the damping rate is 1

Hence, The damping coefficient is 20.

3 0

4 years ago

Se suelta una piedra cerca de la superficie lunar y cae libremente durante 7 segundos. La aceleración de la gravedad lunar es de

Leokris [45]

Answer:

v = 11.2 m/s

Explanation:

A stone is dropped near the lunar surface and falls freely for 7 seconds. The acceleration of lunar gravity is 1.6 m / s², what speed will it reach?

Given that,

The acceleration due to the gravity of lunar gravity is 1.6 m/s²

A stone is dropped near the lunar surface and falls freely for 7 seconds.

We need to find the speed with which it reach.

The initial velocity of the stone will be 0 as it was at rest.

Using equation of kinematics v=u+at

$v=1.6\times 7\\\\v=11.2\ m/s$

So, the stone will reach with a speed of 11.2 m/s

4 0

3 years ago

A loop of area 0.250 m^2 is in a uniform 0.020 0-T magnetic field. If the flux through the loop is 3.83 × 10-3T· m2, what angle

Nostrana [21]

Answer:

40.0⁰

Explanation:

The formula for calculating the magnetic flux is expressed as:

$\phi = BAcos\theta$ where:

$\phi$ is the magnetic flux

B is the magnetic field

A is the cross sectional area

$\theta$ is the angle that the normal to the plane of the loop make with the direction of the magnetic field.

Given

A = 0.250m²

B = 0.020T

$\phi$ = 3.83 × 10⁻³T· m²

3.83 × 10⁻³ = 0.020*0.250cosθ

3.83 × 10⁻³ = 0.005cosθ

cosθ = 0.00383/0.005

cosθ = 0.766

θ = cos⁻¹0.766

θ = 40.0⁰

<em>Hence the angle normal to the plane of the loop make with the direction of the magnetic field is 40.0⁰</em>

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3 years ago

Changes in daily ____ like tracking can lead to constipation

bagirrra123 [75]

Changes in daily <u>routine</u> or <u>lifestyle</u> like traveling can lead to constipation

However, other causes of constipation include the following:

Not observing enough exercise
Eating foods very low in fibers
Dehydration.
Changes in one's regular routine, such as traveling or eating
Over consumption of some food substances such as milk
Resisting the urge to have a bowel movement.
Going late to bed
Eating late at night for some individuals

<h3>What is constipation?</h3>

This is a health condition in whereby there is difficulty in emptying the bowels.

This makes defecation very difficult.

So therefore, changes in daily routine or lifestyle like traveling can lead to constipation

Learn more about changes in life style as one of the causes of constipation:

brainly.com/question/26637572

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2 years ago

The diagram shows waves of sound travelling through the air. By which factor is the sound intensity decreased at 3 meters?

SIZIF [17.4K]

The diagram is missing; however, we know that the intensity of a sound wave is inversely proportional to the square of the distance from the source:
$I(r)= \frac{1}{r^2}$
where I is the intensity and r is the distance from the source.

We can assume for instance that the initial distance from the source is r=1 m, so that we put
$I= \frac{1}{r^2}= \frac{1}{(1)^2}=1$
The intensity at r=3 m will be
$I= \frac{1}{r^2}= \frac{1}{(3)^2}= \frac{1}{9}$
Therefore, the sound intensity has decreased by a factor $1/9$ .

8 0

3 years ago

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