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Keith_Richards [23]
3 years ago
15

If a force of 60 N is exerted on a 15 kg object, calculate the acceleration that the object undergoes. ________ m/s2 4 900 0.25

40
Mathematics
2 answers:
Maurinko [17]3 years ago
5 0

Answer:  The correct option is

(A) 4 m/s.

Step-by-step explanation:  We are given that a force of 60 N is exerted on a 15 kg object.

We are to calculate the acceleration that the object undergoes.

From Newton's second law of motion, we have

F=ma, where m is the mass of the object, a is the acceleration and F is the force exerted.

For the given object, we have

F = 60 N  and  m = 15 kg.

So, we get

F=ma\\\\\Rightarrow 60=15\times a\\\\\Rightarrow a=\dfrac{60}{15}\\\\\Rightarrow a=4.

Thus, the required acceleration that the object undergoes is 4 m/sec.

Option (A) is CORRECT.

Luda [366]3 years ago
4 0
F=m•a
Then:
a=F/m
a=60/15=4 m/s²
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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2762144

_______________


Let  \mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}


\mathsf{0\le \theta\le\pi,}  because that is the range of the inverse cosine funcition.


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\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>

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