keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?
![\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20y%20%3D%20%5Ccfrac%7B2%7D%7B3%7Dx%5Cimplies%20y%20%3D%20%5Cstackrel%7B%5Cstackrel%7Bm%7D%7B%5Cdownarrow%20%7D%7D%7B%5Ccfrac%7B2%7D%7B3%7D%7Dx%2B0%5Cqquad%20%5Cimpliedby%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

Answer:
angle 3 is 140°
Step-by-step explanation:
angle 2 and angle 3 are equal
angle 4 and 1 are also equal
angle 3 =
180-40= 140
angle 3 is 140
Answer:
No they are proprotional.
Step-by-step explanation:
the tables eqaution is
y=3x+1
Answer: Choice B
12.5 < x < 18.9
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Explanation:
We have a triangle with these side lengths:
- a = 10
- b = 16
- c = x = unknown
Let's assume that b = 16 is the largest side of this triangle.
By the converse of the pythagorean theorem, we need
to be true in order for an acute triangle to happen.
So,

Now let's consider the possibility that the missing side x is actually the longest side.
Using the same theorem as before, we would say,

We found that x > 12.5 and x < 18.9
This is the same as saying 12.5 < x and x < 18.9
Put together, they form the approximate answer of 12.5 < x < 18.9