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2 years ago

I'm stuck on C, please help. Thank you

Mathematics

2 answers:

jonny [76]2 years ago

6 0

Step-by-step explanation:

$(x {}^{4} - x) {}^{4} - ( {x}^{4} - x)$

$x {}^{16} + 4( {x}^{12} ) - x + 6( {x}^{8} )( {x}^{2} ) + 4( {x}^{4} )( - {x}^{3} ) + {x}^{4} -( {x}^{4} - x)$

${x}^{16} - 4 {x}^{13} + 6 {x}^{10} - 4 {x}^{7} + {x}^{4} - {x}^{4} + x$

${x}^{16} - 4x {}^{13} + 6 {x}^{10} - 4 {x}^{7} + x$

SashulF [63]2 years ago

5 0

F(f(x)): (x^4-x)^4-x^4+x which equals to:
P.s: there are 4 formats and all of them are correct.

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the number of kilometers a car can drive varies directly with the liters of fuel in the car. this car can travel 476 kilometers

notka56 [123]

For this case we have that the relationship is direct.

Therefore, we have:

$y = k * x$

Where,

y: distance traveled in kilometers

x: number of liters of fuel

k: proportionality constant

We must look for the value of k. For this, we use the following data:

This car can travel 476 kilometers on 17 liters of fuel.

Substituting values we have:

$476 = k * 17$

From here, we clear the value of k:

$k = \frac{476}{17}\\k = 28$

Therefore, the relationship is:

$y = 28x$

For 1428 kilometers we have:

$1428 = 28x$

Clearing the amount of fuel we have:

$x = \frac{1428}{28}\\x = 51$

Answer:

51 liters of fuel are required for the vehicle to travel 1,428 kilometers

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3 years ago

5ab^2 - 12a^2b + 3ab + ab^2 + 4a^2b

Natali [406]

By combining like terms, the answer is a

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3 years ago

The cost of one pound of bananas is greater than $0.41 and less than $0.50. Sarah pays $3.40 for x pounds of bananas. Which ineq

vredina [299]

Answer:

0.41<3.40/x<0.50

Step-by-step explanation:

Given that the cost of one pound of bananas is greater than $0.41 and less than $0.50. That is,

If the cost of one banana is P, then, the inequality will be

0.41 < P < 0.50

Sarah pays $3.40 for x pounds of bananas. The inequality that represents the range of possible pounds purchased will be achieved by below

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Therefore, the inequality that represents the range of possible pounds purchased is

6 < x < 9 this is the same as 0.41<3.40/x<0.50

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3 years ago

A jet moving at constant speed traveled 6,600 km in 3 hours. What was the speed of the jet?

DanielleElmas [232]

Answer:

The speed of the jet is $2,200\frac{km}{h}$

Step-by-step explanation:

The speed traveled by the jet can be found using the relationship between distance and time. Because the problem gives the values for distance and time, they must be replaced in the equation and in this way the requested speed will be found.

1. Write the general equation for the speed:

$Speed=\frac{Distance}{Time}$

2. Replace the values of distance and time on the general equation for the speed and make the mathematical operations:

$Speed=\frac{6,600km}{3hours}$

$Speed=2,200\frac{km}{h}$

Therefore the speed of the jet is $2,200\frac{km}{h}$

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3 years ago

Read 2 more answers

List the opposite of the following numbers: -4, 1, -2.5, 101, 1/2

maksim [4K]

Answer:

Step-by-step explanation:

The opposite of :-

-4=4

1= -1

-2.5= 2.5

101 = -101

1/2= -1/2

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3 years ago