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stiv31 [10]
2 years ago
13

I'm stuck on C, please help. Thank you

Mathematics
2 answers:
jonny [76]2 years ago
6 0

Step-by-step explanation:

(x {}^{4}  - x) {}^{4} -  ( {x}^{4}  - x)

x {}^{16}   +  4( {x}^{12} ) - x + 6( {x}^{8} )( {x}^{2} ) + 4( {x}^{4} )( -  {x}^{3} ) +  {x}^{4}  -(  {x}^{4}  - x)

{x}^{16}  - 4 {x}^{13}  + 6 {x}^{10}  - 4 {x}^{7}  +  {x}^{4}  -  {x}^{4}  + x

{x}^{16}  - 4x {}^{13}  + 6 {x}^{10} - 4 {x}^{7}   + x

SashulF [63]2 years ago
5 0
F(f(x)): (x^4-x)^4-x^4+x which equals to:
P.s: there are 4 formats and all of them are correct.

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Kerry and Tya are sharing a pack of stickers. Each girl gets 11 stickers. Write and solve a division equation to find how many t
Shalnov [3]
Since each girl gets 11 sticker that means that there are 22 stickers in the pack.

11x2=22
4 0
4 years ago
If you double the lengths of a rectangle what can you say about the new area of it.
Natasha_Volkova [10]

Answer:

The answer is B: The area of the new rectangle is double it's original size

5 0
4 years ago
Nancy and Karen went on a trip to the mountain. Nancy started her trip 30 minutes later than Karen. They started from the same p
Katyanochek1 [597]
Distance = (rate)(time)
In this problem, note that both girls traveled the same distance.

Karens distance = r * 1.5 hrs          we dont know her rate
Nancy distance = 50 * 1 hr              we know she started 30 min later
                                                         but arrived at the same time

since the distances are equal
r*1.5 = 50 * 1          all you have to do is solve for r

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3 0
3 years ago
Pleeeeeease help me soon
Tresset [83]

Answer:

The first amount is larger by 25%  or .25a

Step-by-step explanation:

Lets increase a by 50%

The increase is .5a

So the new value is a + .5a = 1.5a

Now we will decrease the new value by 50%

decrease = .5 (1.5a) = .75a

The new value of a is 1.5a - .75a = .75a

a > .75a

a - .75a = .25a

a is bigger than .75a by .25a

3 0
3 years ago
Show all steps!!!
Lunna [17]
-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3
\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12}
\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}
=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}
=-\frac{53}{6}
4 0
3 years ago
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