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zzz [600]
3 years ago
8

Pls I need help with this geometry problem. It's due today.

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0

Step-by-step explanation:

Yz / RT = SZ / ST

2X +2 / 3X -7 = 35 / 40= 7 / 8

8( 2x+2) = 7( 3x-7 )

16 x +16 = 21x 49

5x = 65

x =13

YZ = 2×13 +2 = 28

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Find the coordinates of the other endpoint of the​ segment, given its midpoint and one endpoint.​ (Hint: Let​ (x,y) be the unkno
spin [16.1K]
The other endpoint is (1, -17).

The midpoint formula is:

m=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Using our midpoint and endpoint, we have:
(6, -11) = (\frac{11+x_2}{2}, \frac{-5+y_2}{2})
\\
\\6=\frac{11+x_2}{2} \text{ and } -11=\frac{-5+y_2}{2}


For the first equation (to find the x-coordinate) we will multiply both sides by 2:
6\times2=\frac{11+x_2}{2}\times 2
\\
\\12=11+x_2

Subtract 11 from both sides:
12 - 11 = 11+x₂ - 11
1 = x₂

For the second equation (the y-coordinate) we multiply both sides by 2:
-11\times2=\frac{-5+y_2}{2}\times 2
\\
\\-22=-5+y_2

Add 5 to both sides:
-22+5 = -5+y₂ + 5
-17 = y₂

This means that (x₂, y₂) is at (1, -17).
4 0
3 years ago
What is 451 rounded to the nearest hundred?
USPshnik [31]

Answer:

500

Step-by-step explanation:

If the tens digit is 50 or above then you round up to the next hundred but if it is 49 or below you round down to the nearest hundred

3 0
3 years ago
Read 2 more answers
PLZ HELP I GIVE 15 POINTS
Natali [406]

Answer:

<u>4 1/12. (Four, one by twelve).</u>

Step-by-step explanation:

7/12 × 7 =?

7/12×7 = <u>49/12.</u>

The answer is now in improper fraction. When we convert it to mixed fraction we get the answer as <u>4 1/12. (Four, one by twelve).</u>

8 0
3 years ago
1 over 8 added 5 times equals​
leonid [27]

Answer:

5/8 or 41/8

Step-by-step explanation:

If you mean 1/8 x 5, then that equals 5/8

If mean 1/8 + 5, then that equals 41/8

3 0
3 years ago
Can someone help me with these three? You can get 30 points
lyudmila [28]

Answer:

1 is 4

2 is 3

3 is 6

Step-by-step explanation:

tofu tu ugh uh runs

4 0
3 years ago
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