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3 years ago

Please answer it now in two minutes

Mathematics

1 answer:

makkiz [27]3 years ago

6 0

Answer:

VX = 8.8 in

Step-by-step explanation:

By applying Sine rule in the right triangle WXV,

Sin(∠W) = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

= $\frac{\text{VX}}{\text{WX}}$

Sin(34)° = $\frac{VX}{15}$

VX = 15.Sin(34)°

= 8.8379

≈ 8.8 in.

Therefore, measure of side VX is 8.8 in.

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Calculate the expected value, the variance, and the standard deviation of the given random variable X. (Round all answers to two

Tom [10]

Answer:

E (X) = 1.8

Var (X) = 0.36

σ = 0.6

Step-by-step explanation:

Solution:-

- Denote the random variable X : is the number of red marbles that Suzan has in her hand after she selects three marbles.

- Total sample space (bag) have the following quantity of colored marbles:

Bag : { 3 Red , 2 Green }

- Suzan selects three marbles from the bag. The Event (X) defines the number of red marbles out of 3.

- The total number of outcomes / selections for randomly selecting 3 balls from the bag:

All outcomes = 5 C 3 = 10

- The probability distribution of the random variable X, we will use combinations to determine the required probabilities:

X = 1 red marble:

P ( X = 1 ) : Suzan chooses 1 Red marble from the available 3 red marble and 2 green marbles.

P ( X = 1 ) = [ 3C1*2C2 ] / all outcomes = (3*1) / 10 = 0.3

X = 2 red marble:

P ( X = 2 ) : Suzan chooses 2 Red marble from the available 3 red marble and 1 green marbles.

P ( X = 2 ) = [ 3C2*2C1 ] / all outcomes = (3*2) / 10 = 0.6

X = 3 red marble:

P ( X = 3 ) : Suzan chooses 3 Red marble from the available 3 red marble.

P ( X = 3 ) = [ 3C3] / all outcomes = (1) / 10 = 0.1

- The probability distribution is as follows:

X : 1 2 3

P (X): 0.3 0.6 0.1

- The expected value E(X) for the given random variable X is:

E ( X ) = ∑Xi*P(Xi)

= 1*0.3 + 2*0.6 + 3*0.1

=1.8

- The variance Var(X) for the given random variable X is:

Var ( X ) = ∑Xi^2*P(Xi) - [ E(X) ] ^2

= 1^2*0.3 + 2^2*0.6 + 3^2*0.1 - 1.8^2

= 0.36

- The standard deviation for the given random variable X is:

σ = √Var(X)

σ = √0.36

σ = 0.6

5 0

3 years ago

Which number has the same value as 20 tens

Blizzard [7]

If your still using number blocks then it is 20 ones but if its just addition or so it is just 20

3 0

3 years ago

A package of nine 12-ounce cans of cola costs $7.50. A half-gallon bottle of the same cola is sold for $2.90. Which cola has a c

goldfiish [28.3K]

Answer:

Cola bottles are cheaper. Mark me brainliest!

Step-by-step explanation:

6 0

2 years ago

A test tube is cylindrical in shape with a length of 152 mm and a radius of 6.5 mm. What is the volume of the test tube? Report

vazorg [7]

Answer:

20165

Step-by-step explanation:

Given:

Length/height (h) of cylindrical test tube = 152 mm

Radius of cylindrical test tube = 6.5 mm

Volume = $\pi r^2h$

Required:

Volume of cylinder to nearest whole number

Solution:

The volume is given as $V = \pi r^2h$

Take π as 3.14 and plug the values of r and h into the volume formula.

$V = 3.14*6.5^2*152$

$V = 3.14*6.5*152 = 20165.08$

Volume of the test tube = 20165 mm³ (nearest whole number)

5 0

3 years ago

4 Tan A/1-Tan^4=Tan2A + Sin2A

Eva8 [605]

tan(2A) + sin(2A) = sin(2A)/cos(2A) + sin(2A)

• rewrite tan = sin/cos

… = 1/cos(2A) (sin(2A) + sin(2A) cos(2A))

• expand the functions of 2A using the double angle identities

… = 2/(2 cos²(A) - 1) (sin(A) cos(A) + sin(A) cos(A) (cos²(A) - sin²(A)))

• factor out sin(A) cos(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (1 + cos²(A) - sin²(A))

• simplify the last factor using the Pythagorean identity, 1 - sin²(A) = cos²(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (2 cos²(A))

• rearrange terms in the product

… = 2 sin(A) cos(A) (2 cos²(A))/(2 cos²(A) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(A)

… = 4 sin(A) cos(A) / (2 - 1/cos²(A))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(A) cos(A) / (2 - sec²(A))

• divide through again by cos²(A)

… = (4 sin(A)/cos(A)) / (2/cos²(A) - sec²(A)/cos²(A))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(A) / (2 sec²(A) - sec⁴(A))

• factor out sec²(A) in the denominator

… = 4 tan(A) / (sec²(A) (2 - sec²(A)))

• rewrite using the Pythagorean identity, sec²(A) = 1 + tan²(A)

… = 4 tan(A) / ((1 + tan²(A)) (2 - (1 + tan²(A))))

• simplify

… = 4 tan(A) / ((1 + tan²(A)) (1 - tan²(A)))

• condense the denominator as the difference of squares

… = 4 tan(A) / (1 - tan⁴(A))

(Note that some of these steps are optional or can be done simultaneously)

7 0

2 years ago