Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:

In the given question it is given that the length of the rectangle is 5.5 cm and the area of the rectangle is 220 cm^2.
Length of the rectangle = 5.5 cm
Area of the rectangle = 220 cm^2
Then we already know that
Area of a rectangle = Length * width
So Width of the rectangle = Area of the rectangle/ Length
= 220/5.5
= 2200/55
= 40
So the width of the rectangle is 40 cm.<span>Hope
that you have got the answer you were
looking for.
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You can use the quadratic equation to solve this once you have this set equal to zero. The answers would be roughly 9.6 and -0.6.