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Elza [17]
3 years ago
9

A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What p

ercent of those who passed the second exam also passed the first exam?
80%
1296
30%
48%
Mathematics
1 answer:
Levart [38]3 years ago
3 0
The answer is the last one - 48%
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Answer:

<em>H</em>₀: <em>μ₁ = μ₂= μ₃</em>

<em>Hₐ: </em>At least one of the means is different.

Step-by-step explanation:

Analysis of variance or ANOVA test is used to determine whether the means of different groups are similar or not.

The hypothesis of an ANOVA test for <em>n</em> homogeneous groups is:

H_{0}: \mu_{1}= \mu_{2}= \mu_{3}...= \mu_{n}\\H_{a}: At\ least\ one\ of\ the\ means\ is\ different

In this case the researcher is testing whether the mean bone mineral density is different for the three different groups.

The hypothesis for this test can be defined as follows:

<em>H</em>₀: The mean bone mineral density is not different for the three different groups, i.e. <em>μ₁ = μ₂= μ₃</em>

<em>Hₐ: </em>The mean bone mineral density is different for the three different groups, i.e. at least one of the means is different.

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Suppose when a baseball player gets a hit, a single is twice as likely as a double which is twice as likely as a triple which is
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Answer:

The PMF of B is given by

P(B=0) = 0.7

P(B=1) = 0.16

P(B=2) = 0.08

P(B=3) = 0.04

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Step-by-step explanation:

Let x denote P(B=1), we know that

P(B=0) = 1-0.3 = 0.7

P(B=1) = x

P(B=2) = x/2

P(B=3) = x/4

P(B=4) = x/8

Also, the probabilities should sum 1, thus

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P(B=1) = 0.16

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