Answer: x = −18
Step-by-step explanation:
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-4' to each side of the equation.
4 + -4 + -1x = 22 + -4
Combine like terms: 4 + -4 = 0
0 + -1x = 22 + -4
-1x = 22 + -4
Combine like terms: 22 + -4 = 18
-1x = 18
Divide each side by '-1'.
x = -18
Simplifying
x = -18
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Answer:

Possible values of x: Any from 0 to 5.






Step-by-step explanation:
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this question:

So

Possible values of x: 5 trials, so any value from 0 to 5.
For each value of x calculate p(☓ =x)







Answer:
To find the scale factor of the enlargement, compare the distance between a pair of corresponding points from both shapes.
<u>Shape K</u>
A = (4, 7)
B = (7, 7)
C = (7, 4)
D = (5, 5)
Horizontal distance between A (4, 7) and B (7, 7) = 3 units
<u>Shape L</u>
A' = (0, 11)
B' = (9, 11)
C' = (9, 2)
D' = (3, 5)
Horizontal distance between A' (0, 11) and B' (9, 11) = 9 units
9 ÷ 3 = 3
Therefore, Shape L is an enlargement of Shape K by scale factor 3.
To find the center of dilation (enlargement), draw two lines through 2 corresponding points (e.g. A and A', B and B') - the point of intersection of these lines is the center of dilation.
Therefore, the center of enlargement is (6, 5) (refer to the second attached image).
Answer:
Find the area, how tall is the building?
Your answer is:
:D-48