What is the product of 4x^4y^2 and 5y^4?

Mathematics

1 answer:

7nadin3 [17]3 years ago

3 0

Answer:

20x^4y^6

Step-by-step explanation:

$(4x^4y^2)(5y^4) \\20x^4y^6$

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(2x^2+10x+8) divided(2x+2)

Eduardwww [97]

Answer:

x + 4

Step-by-step explanation:

$\mathrm{Factor}\:2x^2+10x+8:\quad 2\left(x^2+5x+4\right)\\=\frac{2\left(x^2+5x+4\right)}{2x+2}\\\mathrm{Factor}\:2x+2:\quad 2\left(x+1\right)\\=\frac{2\left(x^2+5x+4\right)}{2\left(x+1\right)}\\=\frac{x^2+5x+4}{\left(x+1\right)}\\\mathrm{Factor}\:x^2+5x+4:\quad \left(x+1\right)\left(x+4\right)\\\mathrm{Cancel\:the\:common\:factor:}\:x+1\\=x+4$

<em>Hope this helps and have a great day!</em>

6 0

3 years ago

Help me please I'm on a time limit

olga_2 [115]

The original price times the off price to get how much is the discount 3.25*0.25=0.8125 Subtract the discount from the original price 3.25-0.8125=2.4375=2.44 Or 3.25*0.75=2.4375=2.44

7 0

3 years ago

We are told that the price of basket of fries is drawn from a normal distribution with mean 6 and standard deviation of 2. You w

Masja [62]

Answer:

32.64% probability that you would have enough money to pay for all five baskets of fries

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n can be approximated to a normal distribution with mean

In this problem, we have that:

$\mu = 6, \sigma = 2, n = 5, s = \frac{2}{\sqrt{5}} = 0.8944$

You want to get 5 baskets of fries but you only have $28 in your pocket. What is the probability that you would have enough money to pay for all five baskets of fries?

28/5 = 5.6

So this is the pvalue of Z when X = 5.6.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$