54 as a product of primes
1 answer:
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The correct answer is: if is a root of
, then
is also a root of
.
In fact, every polynomial has real and/or complex solutions. If all solutions are real, we're good. But if not all of them are real, then the complex ones come in couple of conjugate solutions. Since and
are conjugate complex numbers, if one of them is a solution, the other must be as well.