Answer:
49
Step-by-step explanation:
X^2 = 3x + 5
x^2 - 3x - 5 = 0
a(alpha) and b(beta are roots
(x - a)(x - b) = 0
x^2 - (a+b)x + ab = 0
compare coefficients
a+b = 3
ab = -5
solving
(1/a^2 + 1/b^2)
= (a^2 + b^2)/(ab)^2
= (a^2 + 2ab + b^2 - 2ab)/(ab)^2
= [(a+b)^2 - 2ab]/(ab)^2
= [(3)^2 - 2(-5)]/(-5)^2 =...
prove
a^4 = 57a + 70
let x=a,
a^2 = 3a + 5
(a^2)^2 = (3a + 5)^2
a^4 = 9a^2 + 30a + 25
a^4 = 9(3a + 5) + 30a + 25
a^4 = 57a + 70
Answer:
No, because there is only one set of congruent angle
Step-by-step explanation:
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