All categories

2 years ago

Does the construction demonstrate how to bisect a segment correctly by hand?

Mathematics

2 answers:

ad-work [718]2 years ago

8 0

Answer:

Step-by-step explanation:

Aleonysh [2.5K]2 years ago

6 0

Answer:

Yes; the compass was kept at the same width to create the arcs for points C and D.

Step-by-step explanation:

When bisecting a segment by hand the steps are:

-Place the compass on one of the endpoints and open the compass to a distance more than halfway across the segment.

-Swing an arc on either side of the segment.

-Keeping the compass at the same width, place the compass on the other endpoint and swing arcs on either side so that they intersect the first two arcs created.

-Mark the intersection points of the arcs and draw a line through those two points.

-The point where this new line crosses the given segment is the midpoint and divides the segment in half.

Its not b because segment c and d was created when you marked the intersection points of the arcs and just drew a line through those two points; They didn't use a straightedge. its not C because this does demonstrate how to bisect a segment by hand, Also the compass was kept at the same width to create the arcs for points C and D. Its not D because this does demonstrate how to bisect a segment by hand, Also a straightedge was not used to create segment CD.

You might be interested in

Find the value of x. Round your answer to the nearest tenth.<br><br> sin 46(degrees)=x/14

Lostsunrise [7]

$sin 46^{o} = \frac{x}{14} \\ x=14sin 46^{o} \\ =14 \times 0.7193 \\ =10.1$

6 0

2 years ago

Read 2 more answers

Im not sure how to solve this

Irina-Kira [14]

A question:
(5.3 x 10 to the 6th power) + 8.2 10 to the 6th power)
A solution:
Multiply 10 x 10 6 times to get rid of the two powers.
(5.3 x 1,000,000) + (8.2 x 1,000,000)
Multiply inside the parenthises.
(5,300,000) + (8,200,000)
Add:
13,500,000.
A answer:
13, 500,000.

B question:
(6.5 x 10 to the 7th power) / (5 x 10 to the 3rd power)
B solution:
Again, get rid of the powers.
(6.5 x 10,000,000) / (5 x 1,000)
Multiply inside the parenthesis:
(65,000,000) / (5,000)
Divide:
13,000
B answer:
13,000.

C question:
(4.6 x 10 to the 6th power) (3 x 10 to the 5th power) / (2 x 10 to the 7th power)
C solution:
Get rid of powers:
(4.6 x 1,000,000) (3 x 100,000) / (2 x 10,000,000)
Multiply:
(4,600,000) (300,000) / (20,000,000)
multiply in the left side:
(1,380,000,000,000) / (20,000,000)
divide:
69,000
C answer:
69,000

8 0

2 years ago

The green family went out for dinner at their favorite restaurant. the cost of their food came to $52.00. they must also pay 6%

riadik2000 [5.3K]

$52 × .06 = 3.12
52 + 3.12 = 55.12
55.12 × 0.15 = 8.27
55.12 + 8.27 = 63.39

7 0

3 years ago

Thanks guys for the help. This one and one more and I’m done!

Karolina [17]

Answer: $60n^{3}$

Step-by-step explanation:

To find the least common multiply, you must descompose 12 and 15 into their prime factors, as you can see below:

12=2*2*3=2²*3

15=3*5

Choose the common and non common numbers with their greastest exponents:

3*5*2²=60

Now you must choose the common and non common variables with their greastest exponents:

n³

Therefore, you can conclude that the least common multiply is:

$60n^{3}$

8 0

3 years ago

Read 2 more answers

Una torre de 28.2 m de altura esta situada a la orilla de un rio, desde lo alto del edificio el ángulo de depresión a la orilla

Svet_ta [14]

Answer:

El ancho del río es 59.9 metros.

Step-by-step explanation:

El ancho del río lo podemos calcular con la siguiente relación trigonométrica asumiendo que la torre forma un triángulo rectángulo con el río:

$tan(\theta) = \frac{CO}{CA}$

En donde:

CA: es el cateto adyacente = Altura de la torre = 28.2 m

CO: es el cateto opuesto = ancho del río =?

θ: es el ángulo adyacente a CA

Dado que el ángulo de depresión (25.2°) está ubicado fuera de la parte superior de la hipotenusa del triángulo que forma la torre con la orilla opuesta del río, debemos calcular el ángulo interno (θ) como sigue:

$\theta = (90 - 25.2)^{\circ} = 64.8 ^{\circ}$

Ahora, el ancho del río es:

$CO = tan(\alpha)*CA = tan(64.8)*28.2 = 59.9 m$

Por lo tanto, el ancho del río es 59.9 metros.

Espero que te sea de utilidad!

4 0

2 years ago