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2 years ago

7

Find four consecutive integers such that twice the sum of the first and third is

1 answer:

disa [49]2 years ago

6 0

Answer:

Hi,Can You answer mine too please I really need the answer because I have to pass it tomorrow morning at my 1st class:(can you please check my question I'll mark you BRAINLIEST:)I hope you can help me:)

Step-by-step explanation:

about your question I'll just put it in the comment section:)

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How is a tangent different from a chord? Explain.

Anastasy [175]

Answer:

The tangent intersects the curve only one point while the chord will intersect the curve at more than one point.

Step-by-step explanation:

A tangent will touch the curve while the chord cuts the curve.

The tangent intersects the curve only one point while the chord will intersect the curve at more than one point.

From the diagram in the attachment line BD is a tangent while line BC is a chord.

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Which of these coordinates would represent the intercepts of the graph of the function f(x)=3x-9

4vir4ik [10]

(3,0) and (0,-9)
Explanation: type the equation in a graphing calculator and the answer is the points where the line crosses the x and y axis

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2 years ago

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Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

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2 years ago

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gulaghasi [49]

Answer:

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Step-by-step explanation:

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