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V125BC [204]
3 years ago
6

Find the equation in slope-intercept form that describes a line through (4, 2) with slope 1/2

Mathematics
1 answer:
monitta3 years ago
8 0

Answer:

The equation in slope-intercept form that describes a line through (4, 2) with  slope \frac{1}{2} is y = \frac{1}{2}x

<u>Solution:</u>

In the question it is given that the line passes through the points (4,2) which has a slope (m) = \frac{1}{2}

We have to find the slope intercept form of the line

We know the slope intercept form of a line is given by  

y = mx +c  where m is the slope of the equation

Here y = 2 ,x = 4 and m =  \frac{1}{2}  

Substituting the values in slope intercept form equation we get

\begin{array}{l}{2=\frac{1}{2} \times 4+c} \\\\ {\Rightarrow 2=2+c} \\\\ {\Rightarrow 2-2=c} \\\\ {c=0}\end{array}

Thus the equation in slope-intercept form that describes a line through (4, 2) with  slope \frac{1}{2} is y = \frac{1}{2}x

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Inessa [10]
The answer is 1358.70
8 0
3 years ago
I’ve never been so confused, this is due in a few minutes, pls help if you can!
algol13

Given:

m(ar QT) = 220

m∠P = 54

To find:

The measure of arc RS.

Solution:

PQ and PT are secants intersect outside a circle.

<em>If two secants intersects outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>

$\Rightarrow \angle P = \frac{1}{2} (m \ ar (QT) - m \ ar (RS ))

$\Rightarrow 54 = \frac{1}{2} (220- m \ ar (RS ))

Multiply by 2 on both sides.

$\Rightarrow 2 \times 54 = 2 \times  \frac{1}{2} (220- m \ ar (RS ))

$\Rightarrow 108= 220- m \ ar (RS )

Subtract 220 from both sides.

$\Rightarrow 108-220= 220- m \ ar (RS )-220

$\Rightarrow -112= -m \ ar (RS )

Multiply by (-1) on both sides.

$\Rightarrow (-112)\times(-1)= -m \ ar (RS )\times(-1)

$\Rightarrow 112= m \ ar (RS )

The measure of arc RS is 112.

6 0
3 years ago
3
Serjik [45]

Step-by-step explanation:

=  \frac{ \frac{3}{x - 2} - 5 }{2 -  \frac{4}{x - 2} }

=  \frac{ \frac{3 - 5.(x - 2)}{x - 2} }{ \frac{2.(x - 2) - 4}{x - 2} }

=  \frac{ \frac{3 - 5.(x - 2)}{ \cancel{x - 2}} }{ \frac{2.(x - 2) - 4}{ \cancel{x - 2} }}

=  \frac{3 - 5.(x - 2)}{2.(x - 2) - 4}

=  \frac{3 - 5x + 10}{2x - 4 - 4}

=  \frac{ - 5x + 13}{2x - 8}

=  \frac{13 - 5x}{2x - 8}

The answer is D.

8 0
2 years ago
5 3/2 x 3 6/7 you have 10 point to do the answer
pogonyaev

Step-by-step explanation:

Conversion a mixed number 5 3/2

to an improper fraction: 5 3/2 = 5 3/2

= 5 · 2 + 3/2

= 10 + 3/2

= 13/2

To find a new numerator:

a) Multiply the whole number 5 by the denominator 2. Whole number 5 equally 5 * 2/2

= 10/2

b) Add the answer from previous step 10 to the numerator 3. New numerator is 10 + 3 = 13

c) Write a previous answer (new numerator 13) over the denominator 2.

Five and three halfs is thirteen halfs

Conversion a mixed number 3 6/7

to an improper fraction: 3 6/7 = 3 6/7

improper fraction: 3 6/7 = 3 6/7

3 · 7 + 6/7 = 21 + 6/7 =27/7

To find a new numerator:

a) Multiply the whole number 3 by the denominator 7. Whole number 3 equally 3 * 7/7

= 21/7

b) Add the answer from previous step 21 to the numerator 6. New numerator is 21 + 6 = 27

c) Write a previous answer (new numerator 27) over the denominator 7.

Three and six sevenths is twenty-seven sevenths

Multiple:

13/2 * 27/7 = 13/2 · 27/7 = 351/14

3 0
2 years ago
Let v be an eigenvector of a matrix A with a corresponding eigenvalue ?=2. Find one solution x of the system Ax=v.
Murljashka [212]

Answer with explanation:

For, a Matrix A , having eigenvector 'v' has eigenvalue =2

 The order of matrix is not given.

It has one eigenvalue it means it is of order , 1×1.

→A=[a]

Determinant [a-k I]=0, where k is eigenvalue of the given matrix.

It is given that,

k=2

For, k=2, the matrix [a-2 I] will become singular,that is

→ Determinant |a-2 I|=0

→I=[1]

→a=2

Let , v be the corresponding eigenvector of the given eigenvalue.

→[a-I] v=0

→[2-1] v=[0]

→[v]=[0]

→v=0

Now, corresponding eigenvector(v), when eigenvalue is 2 =0

 We have to find solution of the system

→Ax=v

→[2] x=0

→[2 x] =[0]

→x=0, is one solution of the system.

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4 years ago
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