C+3c is 4c and -4+9 is 5 so your answer is 4c+5
Use the sin identity to find that side. Sin(30) = a/12...12 sin(30) = a, and a = 6
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Jk, I got you fam
12(t + 2) + 4 ≥ - 8
12t + 24 + 4 ≥ - 8
12t + 28 ≥ - 8
12t ≥ - 8 - 28
12t ≥ - 36
t ≥ - 36 ÷ 12
t ≥ - 3
Solution:
t ≥ -3
Yes because they are constant throughout the table.
Answer:
9 tens = 90
5 hundreds = 500
3 ones = 3
on adding them we get, 500 + 90 + 3 = 593
