Answer:
1) (c)∠ G = 34°
2) (a) x = 33°
3) (d) The perpendicular segments are JM, KL, PQ AND NR.
Step-by-step explanation:
Here in the given questions:
1) p II r
⇒ ∠ G = 34° (ALTERNATE EXTERIOR ANGLES)
Hence, the measure of ∠ G = 34°
2) In the given triangle:
The measure of exterior angle is always the sum of interior opposite angles.
⇒ Here, x + 72° = 105°
or, x = 105° - 72° = 33° , or x = 33°
3) The given plane in the cube is JKPN
The segments which have J , K , P and N as their one vertex are perpendicular to the given plane.
Hence, the segments are JM, KL, PQ AND NR.
Is this
-6 ÷ 20 + 150%
or is -6/20 a fraction?
Answer:
A. 6
Step-by-step explanation:
pretty sure its right
Answer:
(2, -8)
Step-by-step explanation:
(x, y)=(-3, -1)
(x1+x2)/2=-3,
(y2+y2)/2=-1,
-------------------
(x1+x2)/2=-3
(y1+y2)/2=-1
---------------------
x1-8=-6
x1=2
----------
y1+6=-2
y1=-8
(2, -8)
Answer: Original expression: 2x - 11 + 4x + 7 + 3(x-4)
Simplified: 9x - 16
Step-by-step explanation:
2x - 11 + 4x + 7 + 3(x-4) becomes 2x - 11 + 4x + 7 + 3x -12
Group like terms, then combine to simplify:
2x + 4x + 3x -11 + 7 - 12
2x + 4x + 3x = 9x
-11 -12 + 7 = =23+7= -16
Simplified expression: 9x - 16
