mass O₂ required : 0.054 g
<h3>
Further explanation
</h3>
The reaction equation is the chemical formula of reagents and product substances
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products
Reaction
4Fe(OH)⁺ (aq) + 4OH⁻ (aq) + O₂ (g)+ 2H₂O (l)⇒ 4Fe(OH)₃ (s)
To precipitate Fe²⁺(in Fe(OH⁺) to Fe³⁺(in Fe(OH)₃)

mol ratio from equation = mol O₂ :mol Fe(OH) = 1 : 4


Answer:
░░░░░▐▀█▀▌░░░░▀█▄░░░
░░░░░▐█▄█▌░░░░░░▀█▄░░
░░░░░░▀▄▀░░░▄▄▄▄▄▀▀░░
░░░░▄▄▄██▀▀▀▀░░░░░░░
░░░█▀▄▄▄█░▀▀░░
░░░▌░▄▄▄▐▌▀▀▀░░ This is Bob
▄░▐░░░▄▄░█░▀▀ ░░
▀█▌░░░▄░▀█▀░▀ ░░ Copy And Paste Him onto all of ur brainly answers
░░░░░░░▄▄▐▌▄▄░░░ So, He Can Take
░░░░░░░▀███▀█░▄░░ Over brainly
░░░░░░▐▌▀▄▀▄▀▐▄░░
░░░░░░▐▀░░░░░░▐▌░░
░░░░░░█░░░░░░░░█░
do it or he will hunt you down and kill u (lets destroy the moderators!!!!!!!!)
Explanation:
We know that the molarity of a solution is calculated by the following equation:

That being said we are given two of the 3 things that we need: Volume of water, as well as the molarity of the solution. Let's plug those in to the equation to find how many moles of

that we need:

=>

This means that we have 0.04 moles of

.
In order to calculate the number of grams that we need for this solution, we must first calculate how many grams of

are in 1 mole. We do this by taking the atomic masses of each element from the periodic table and adding them together.
Na = 22.99 g
S = 32.06 g
We have 2 Na's, and we have 1 S. So lets add them together:
2(22.99) + (32.06) =

.
Since we need 0.04 moles of

, we can multiply the molar weight of the molecule times the amount of moles needed to find the total grams that we need for the solution:

Now we know that in order to make a 0.2 M solution of

, we must use
3.1216 grams.
Answer:
Noble gasses
Explanation:
nobled gasses
all elements want to loose or gain electrons to be like the noble gasses in bonding but the noble gasses do not bond.
Answer:
Specific gravity is the density of asubstance divided by the density of water. Since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density(but without any units).