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2 years ago

Magnesium +Hydrogen Phospahate

Chemistry

2 answers:

Aleks04 [339]2 years ago

8 0

Answer:

That makes Dimagnesium phosphate

Mekhanik [1.2K]2 years ago

6 0

Answer:

The reaction between Magnesium and Hydrogen Phosphate forms Magnesium Hydrogen Phosphate

Explanation:

When magnesium reacts with hydrogen phosphate it forms an ionic compound called Magnesium Hydrogen Phosphate or Dimagnesium Phosphate.

Magnesium Hydrogen Phosphate is an ionic compound with the formula HMgO4P.

Equation;

Mg + HPO4 ------> HMgO4P

Similarly we can use Magnesium Phosphate to demonstrate the reaction.

In chemistry, the sum of charges of the anion and the cation of any ionic compound is always equal to zero.

To determine the number of anion and cation required for the sum to be zero we simply use the criss-cross method. This involves taking the charge of one ion and making the absolute value of that charge to be the amount of the other ion.

Therefore, Magnesium having a charge of 2+; we will have two(2) Phosphate cations for it.

Also, Phosphate has a charge of 3-; so we have three(3) Magnesium cations.

Equation;

$Mg^{2+} + (PO4)^{3-} ----> Mg3(PO4)2$

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2 years ago

Two 0.75 Amp loads are connected in parallel with a 2500 Milliamperehour Ni-Cd battery. Approximately how long can the battery p

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Explanation:

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As both the loads are connected in parallel. Hence, total current will be calculated as follows.

I = $I_{1} + I_{2}$

= 0.75 A + 0.75 A

= 1.5 A

= $1.5 A \times \frac{1000 mA}{1 A}$

= 1500 mA

Relation between time and capacity of battery is as follows.

Capacity = Current × time (in hour)

therefore, time = $\frac{Capacity}{Current}$

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Thus, we can conclude that the battery provide power to the load up to 1.667 hours.

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3 years ago

A 3.00 L flexible container holds a sample of hydrogen gas at 153 kPa. If the pressure increases to 203 kPa and the temperature

dybincka [34]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

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V2 = 153 x 3.00 / 203

V2 = 2.26 L

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2 years ago

A buffer solution contains 0.20 mol of propionic acid (CH3CH2COOH) and 0.25 mol of sodium propionate (CH3CH2COONa) in 1.50 dm3.

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Answer:

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3 years ago

Calculate the pH of a solution prepared by mixing: (Show your work for these calculations) pk of acetic acid is 4.75 a. two mole

kupik [55]

Answer:

Explanation:

To calculate pH you need to use Henderson-Hasselbalch formula:

pH = pka + log₁₀ $\frac{[A^-]}{[HA]}$

Where HA is the acid concentration and A⁻ is the conjugate base concentration.

The equilibrium of acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka: 4,75

Where CH₃COOH is the acid and CH₃COO⁻ is the conjugate base.

Thus, Henderson-Hasselbalch formula for acetic acid equilibrium is:

pH = 4,75 + log₁₀ $\frac{[CH_{3}COO^-]}{[CH_{3}COOH]}$

a) The pH is:

pH = 4,75 + log₁₀ $\frac{[2 mol]}{[2 mol]}$

pH = 4,75

b) The pH is:

pH = 4,75 + log₁₀ $\frac{[2 mol]}{[1mol]}$

pH = 5,05

I hope it helps!

7 0

3 years ago