Answer:
0.0023 cm
Explanation:
The following data were obtained from the question:
Length (L) = 55 cm
Breadth (B) = 23.3 cm
Volume (V) = 2.9 cm³
Thickness (T) =?
Thus, we can obtain the thickness of the aluminum foil as illustrated below:
V = L × B × T
2.9 = 55 × 23.3 × T
2.9 = 1281.5 × T
Divide both side by 1281.5
T = 2.9/1281.5
T = 0.0023 cm
Therefore, the thickness of the aluminum foil is 0.0023 cm
You know oxygen is the limiting reactant (since it says there is excess hydrogen). So, use stoichiometry based on the given number of oxygen moles:
Answer:
The main purpose for converting numbers into scientific notation is to make calculations with surpisingly large or small numbers less complicated. Since zeros are not used to place the decimal point, all of the digits in a number in scientific notation are meaningful and easier to read. Hope this helps!
Explanation:
Answer:
(1) <em>C</em> C3H7OH = 9.200 M
(2) <em>C</em> C3H7OH = 11.647 m
Explanation:
mixture:
∴ 70% = (g C3H7OH/g mix)×100
∴ 30% = (gH2O/g mix)×100
∴ δ mix = 0.79 g/mL
assuming:
⇒ V mix = (100g)×(mL/0.79g) = 126.582 mL mix = 0.1266 L mix
⇒ g C3H7OH = 70g
⇒ g H2O = 30g
∴ Mw C3H7OH = 60.1 g/mol
∴ Mw H2O = 18 g/mol
(1) Molar concentration (M):
⇒ <em>C</em> C3H7OH = ((70 g)(mol/60.1 g))/(0.1266L) = 9.200 M
(2) molal concentration (m):
⇒ <em>C </em>C3H7OH = ((70 g)(mol/60.1g))/(0.100 Kg) = 11.647 m
