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guajiro [1.7K]
4 years ago
9

Which expression is equivalent to 24∧ 1/3?

Mathematics
2 answers:
beks73 [17]4 years ago
4 0
It should be the third root of 24 or 2 on the outside of the third root of 3
oksian1 [2.3K]4 years ago
3 0

Answer:

2\sqrt[3]{3}.

Step-by-step explanation:

We have been given an expression 24^{\frac{1}{3}}. We are supposed to express our given expression in another form.

Using exponent property a^{\frac{1}{n}=\sqrt[n]{a}, we can write our given expression as:

24^{\frac{1}{3}}=\sqrt[3]{24}

We can write 24 as product of 8 and 3.

24^{\frac{1}{3}}=\sqrt[3]{8\cdot 3}

24^{\frac{1}{3}}=\sqrt[3]{2^2\cdot 3}

Using exponent property \sqrt[n]{a^n}=a, we will get:

24^{\frac{1}{3}}=2\sqrt[3]{3}

Therefore, the equivalent expression is 2\sqrt[3]{3}.

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\text{Use the distributive property:}\\\\a(b+c)=ab+ac

2(x+5)+3(x^2-5x+13)=(2)(x)+(2)(5)+(3)(x^2)-(3)(5x)+(3)(13)\\\\=2x+10+3x^2-15x+39=3x^2-13x+49

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What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
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Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

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First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

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Answer:

Step-by-step explanation:

A diameter of the circle.

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By definition of conditional probability,

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