Answer:
We don't have the ability to tell
Step-by-step explanation:
(no image provided) Error: 362
Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
Answer:
Problem 1:
a. x=2
b. x=3
c. x=1
Problem 2:
A multiplication equation to hold the table true:

A division equation to hold the table true:

Step-by-step explanation:
Given in problem 1:
(a). The equation is 
It holds true for all values of
.
Let us say
,
which is greater than 1.
(b). The equation is 
It holds true for all values of
.
Let us say 
which is less than 1.
(c). The equation is 
It holds true for only
.
Let us say
,
which is equal to 1.
Problem 2:
A multiplication equation to hold the table true:

A division equation to hold the table true:

Therefore these are the values which hold true to the equation in problem 1 and 2.
Answer:
he will owe $1,047 in total and $97.37 in interest