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Musya8 [376]
3 years ago
10

PLEASE HELP: Explain what the Pythagorean theorem is, and when it's used. Then, create a problem that requires you to solve usin

g the Pythagorean Theorem, and then solve the problem. (Show all your work) Lastly, give an example where you can use Pythagorean Theorem in real life. This question has 4 parts. Answer all for full credit.
Mathematics
1 answer:
bearhunter [10]3 years ago
7 0
The Pythagorean theorem is a mathematical process which allows us to find a missing side to a triangle. The formula for the Pythagorean theorem is: a^2 + b^2 = c^2.

Example problem:
2^2 + 4^2 = c^
4 + 16 = C
20 = C
4.47 = C^2
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3x + 12+ 9x - 72<br><br><br>Solve?​
Reil [10]

Answer:

12x - 60

Step-by-step explanation:

3x+12+9x-72\\=3x+9x+12-72\\=12x+12-72\\=12x-60

5 0
2 years ago
What is the average daily balance for the February 1-28 billing period in the table?​
givi [52]
I think it’s 311.75?
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6 0
1 year ago
A particle moves along the curve below. y = √ 3 + x 3 y=3+x3 As it reaches the point ( 1 , 2 ) (1,2), the y y-coordinate is incr
nydimaria [60]

Answer:

The x-coordinate of the point changing at ¼cm/s

Step-by-step explanation:

Given

y = √(3 + x³)

Point (1,2)

Increment Rate = dy/dt = 3cm/s

To calculate how fast is the x-coordinate of the point changing at that instant?

First, we calculate dy/dx

if y = √(3 + x³)

dy/dx = 3x²/(2√(3 + x³))

At (x,y) = (1,2)

dy/dx = 3(1)²/(2√(3 + 1³))

dy/dx = 3/2√4

dy/dx = 3/(2*2)

dy/dx = ¾

Then we calculate dx/dt

dx/dt = dy/dt ÷ dy/dx

Where dy/dx = ¾ and dy/dt = 3

dx/dt = ¾ ÷ 3

dx/dt = ¾ * ⅓

dx/dt = ¼cm/s

The x-coordinate of the point changing at ¼cm/s

7 0
3 years ago
Translate the sentence into an equation.
Liula [17]

Answer:

b + 2 = 6

Step-by-step explanation:

This may not be the right answer, but its what I think it is.

3 0
3 years ago
Identify the missing symbol<br>2√15?√60
madreJ [45]
X + 7x = 56 + 8

Simplifying x + 7x = 56 + 8 Combine like terms: x + 7x = 8x 8x = 56 + 8 Combine like terms: 56 + 8 = 64 8x = 64 Solving 8x = 64 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Divide each side by '8'. x = 8 Simplifying x = 8
8 0
3 years ago
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