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Aleks04 [339]
3 years ago
5

F(x) = x^2 - 4, X is greater/less than 0 (a) Find the inverse function of f. F^-1(x) =

Mathematics
1 answer:
Natali5045456 [20]3 years ago
7 0

Step-by-step explanation:

f(x) = x² - 4

y = x²-4

x = y²-4

x + 4 = y²

y =  \sqrt{x + 4}

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Use the unit circle to evaluate these expressions:
sergeinik [125]

Answer:

a) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4

For this case we know that sin (\pi/4) = \frac{\sqrt{2}}{2}

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b) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

19 \pi/6 - 2\pi = \frac{7\pi}{6}

For this case we know that cos (\pi/6) = \frac{\sqrt{3}}{2}

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So from definition of tan we have this:

tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0

Step-by-step explanation:

a. sin (17pi / 4 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4

For this case we know that sin (\pi/4) = \frac{\sqrt{2}}{2}

So then sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}

b. cos (19pi / 6 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to 2\pi:

19 \pi/6 - 2\pi = \frac{7\pi}{6}

For this case we know that cos (\pi/6) = \frac{\sqrt{3}}{2}

And we know that \frac{7\pi}{6} is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}

c. tan(450pi)

For this case that any factor of \pi the sin function is equal to 0.

So from definition of tan we have this:

tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0

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Answer:

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