Answer:
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
Use secant-tangent product theorem.
1. Set up the equation
(x-3)(x-3+5) = (x-1)²
2. Solve
(x-3)(x+2) = (x²-2x+1)
(x²-x-6) = (x²-2x+1)
3. Solve for x
Subtract x² from both sides
-x-6 = -2x+1
Add 2x and 6 to both sides
x = 7
1. 3x^1 + 8 - (2x^2 + 1).....distribute the negative thru the parenthesis
3x^1 + 8 - 2x^2 - 1....now combine like terms
-2x^2 + 3x^1 + 7
2. 5x^2 + 3x - 4 - (x^2 - 6x)...same thing..distribute
5x^2 + 3x - 4 - x^2 + 6x...combine like terms
4x^2 + 9x - 4
Answer:
4 : 3
Step-by-step explanation:
QRS to VUT

