Answer:
The mean of sampling distribution of the proportion of the students who prefer later start times for school
μₓ = p = 0.63
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given sample size 'n' =200
given data Of the 200 students surveyed at the local high school, 126 say that they prefer earlier start times for school
sample proportion

The mean of sampling distribution of the proportion of the students who prefer later start times for school
μₓ = p = 0.63
Standard deviation of the proportion

Answer:
Number 25: B or C idk
Number 26: D 1.50M
Tell me if im right i tried sorry if not
Step-by-step explanation:
Answer:
x = 17
Step-by-step explanation:
Given
(y + 5) + 3y = x ← substitute y = 3
(3 + 5) + 3(3) = x, that is
8 + 9 = x, thus
x = 17
100. 21
------ = -----------
x. 13
21x = 1,300
------ ---------
21. 21
x = 61.9