Answer:
The answer to your question is below
Step-by-step explanation:
A) 2x > -6
x > -6/2
x > -3
It must be a graph with an open circle starting at -3 and then to the right.
It is the first graph.
B) x - 4 < -7
x < -7 + 4
x < -3
The graph must be an open circle starting at -3 and pointing to the left.
it is the second graph.
C) 6 + x ≤ 3
x ≤ -6 + 3
x ≤ -3
The graph must be a closed circle starting at -3 and pointing to the left.
it is the forth graph.
D) -x - 5 ≤ -2
-x ≤ -2 + 5
- x ≤ 3
x ≥ -3
The graph must be a closed circle starting at -3 and pointing to the right.
It is the third graph.
So, each square on the grid is 10 inches in length and width
To find the dimension of the diagonal lengths, treat them like a hypotenuse so we can use the Pythagorean theorem.
a^2 + b^2 = c ^2
a and b are our length and width and c is the hypotenuse.
Make each diagonal length part of a triangle. There will then be 4 triangles to work with.
Triangle 1 (Top left)
Triangle 2 (Bottom left)
Triangle 3 (Top Right)
Triangle 4 (Bottom Right)
A right triangle made with the top left diagonal dimension will have a vertical dimension of 30 (10+10+10) and a horizontal dimension of 40 (10+10+10+10)
To find c or the hypotenuse, plug these into the Pythagorean theorem.
30^2 + 40^2 = c ^2
c^2 = 900 + 1600 = 2500
c = sqrt(2500) = 50
You will see that triangles 2, 3, and 4 have the same vertical and horizontal dimensions giving them the same value.
Now combine the dimensions
diagonal = 50+50+50+50 = 200
horizontal = 90+90 = 180
diagonal + horizontal = 380
