You want to try and get rid of one of the variables ( x or y) so you would multiply the second equation by 2 which would make the x variable -2x which then when added to the first equation would eliminate the x variable.

Answer: c. Multiply the second equation by 2.

4 0

3 years ago

8/7=x/5 what is the value of x round to the nearest tenth

faust18 [17]

Answer:

Step-by-step explanation:

$\frac{8}{7} = \frac{x}{5}$

To find x first cross multiply

We have

7x = 8 × 5

7x = 40

Divide both sides by 7

That's

$\frac{7x}{7} = \frac{40}{7}$

$x = \frac{40}{7}$

x = 5.7142

We have the final answer as

<h3>x = 5.7 to the nearest tenth</h3>

Hope this helps you

7 0

3 years ago

Read 2 more answers

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then