The first equation
6x^2 -18x-24=0
-the graph opens up
6(x^2 -3x -4)=0
6(x^2 -3x +9/4-4-9/4)=0
6(x-3/2)-25x6/4=
6(x-3/2)-75/2
-Vertex is at (3/2, -75/2)
-Axis of symmetry is x=3/2
Second equation
3r^2 -16r -12=0
-the graph opens up
...
Answer:
i'm guessing a positive test result
Step-by-step explanation:
The answer is [ ∠A ≅ ∠A; A F/AB = AG/AC = 3 ]
Both triangles are the same just different sizes.
The length of A F is 9 units. The length of AB is 3 units.
To find the scale factor, just divide.
9 / 3 = 3
The length of AG is 6 units. The length of AC is 2 units.
To find the scale factor, just divide.
6 / 2 = 3
The only logical answer is B because the ratio's are written to where when you solve them, you get the scale factor 3.
Best of Luck!
