AO = 21
BC = 14
OC = radius of the circle = AO = 21
∴ OB = OC + CB = 21 + 14 = 35
<span>Line AB is tangent to circle O at A</span>
∴ AB is perpendicular to AO
∴ Δ OAB is a right triangle at A
Applying Pythagorean theorem
∴ OB² = AO² + AB²
∴ AB² = OB² - AO² = 35² - 21² = 1225 - 441 = 784
∴ AB = √784 = 28
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Answer:
C. X^3-12x^2+2x-24
D. x^3-12x^2-2x-24
Its between these two. There's one with a negative 2x and the other with a positive 2x.
Step-by-step explanation:
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Answer:
-1/53
Step-by-step explanation:
Answer:
none
Step-by-step explanation:
A. -7+4x=9 4x=9+7 x=4
B. x= -1
C. x = -32/19
D. x = -6
E. x = -12
F. x= 0
