It’s easy just make a line and put numbers each line to solve the linear equation and than solve it simple
The capacity is the same as the amount because it refers to the amount of what is inside the object. Lets say you have a bag of chips it refers to the amount inside the bag of chips.
Answer: The cost of one bag of chips is $1.5 and cost of one bag of pretzels is $1.05.
Step-by-step explanation:
Let x= Cost of one bag of chips
y= Cost of one bag of pretzels.
As per given, we have
5x+9y=16.95 ...(i)
x+y=2.55 ...(ii)
Multiply 5 to (ii), we get
5x+5y=12.75 ...(iii)
Eliminate (iii) from (i), we get

Put value of y in (ii), we get

Hence, the cost of one bag of chips is $1.5 and cost of one bag of pretzels is $1.05.
The formula is
A=p (1+r/k)^kt
A accumulated amount?
P principle 3000
R interest rate 0.03
K compounded semiannually 2
T time 6 years
A=3,000×(1+0.03÷2)^(2×6)
A=3,586.85
Answer:
a. Class width=4
b.
Class midpoints
46.5
50.5
54.5
58.5
62.5
66.5
70.5
c.
Class boundaries
44.5-48.5
48.5-52.5
52.5-56.5
57.5-60.5
60.5-64.5
64.5-68.5
68.5-72.5
Step-by-step explanation:
There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,
Class
Interval frequency
45-48 1
49-52 3
53-56 5
57-60 11
61-64 7
65-68 7
69-72 1
a)
Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.
Class width=49-45=4
b)
The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

Class
Interval Midpoints
45-48 
49-52 
53-56 
57-60 
61-64 
65-68 
69-72 
c)
Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.
Class
Interval Class boundary
45-48 44.5-48.5
49-52 48.5-52.5
53-56 52.5-56.5
57-60 56.5-60.5
61-64 60.5-64.5
65-68 64.5-68.5
69-72 68.5-72.5