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Phoenix [80]
3 years ago
15

There is no sodium found in nature in pure form due to its reactivity. What does this say about activation energy of the reactio

n of sodium and water compared to the combustion of wax in a candle?
Chemistry
1 answer:
Yuki888 [10]3 years ago
7 0

Answer:

The activation energy of a chemical reaction is the energy that is required to be supplied for a chemical reaction to take place. The activation energy for the reaction of sodium is low compared to the energy released such that the reaction of sodium and water is spontaneous resulting in the melting of the sodium into liquid form

The activation energy of a candle wax is much higher, requiring the ignition of the wick which burns and in turn melts the candle wax to release vapors that burns alongside the wick to produce sooth carbon dioxide, carbon monoxide and water vapor and release of heat energy which also fuels further combustion of the candle wax and wick

Therefore, the activation energy of the candle wax and wick which require the heat of direct flame from an ignited matches is higher than the activation energy of sodium placed in a medium of water that reacts spontaneously without heat application

Explanation:

You might be interested in
for the reaction C+2H2= Ch4 how many molecules of hydrogen are required to produce 14 grams of methane Ch4?
Nina [5.8K]

Answer:

mass of CH4 = 14

Molecular mass of CH4 16.04gmol

No of mole of CH4 = 14/16.04

No of mole of CH4 = 0.8728mol

Stoichiometrically, from the above

2 Molecules of Hydrogen will produce 1molecule of methane

Therefore, 2*0.8728 mole of Hydrogen will produce 0.8728mol of Methane.

The no of molecule of hydrogen is 1.7456

5 0
3 years ago
10. A small gold nugget has volume of 0.87 cm3. What is its mass if the density of gold is 19.3 g/cm3?
bulgar [2K]

Answer:

16.791 grams

Explanation:

The density formula is:

d=\frac{m}{v}

Rearrange the formula for m, the mass. Multiply both sides of the equation by v.

d*v=\frac{m}{v}*v

d*v=m

The mass of the gold nugget can be found by multiplying the density and volume. The density is 19.3 grams per cubic centimeter and the volume is 0.87 cubic centimeters.

d= 19.3 g/cm^3\\v-0.87 cm^3

Substitute the values into the formula.

m=d*v

m= 19.3 g/cm^3*0.87 cm^3

Multiply. Note that the cubic centimeters, or cm³ will cancel each other out.

m=19.3 g*0.87

m=16.791 g

The mass of the gold nugget is 16.791 grams.

8 0
3 years ago
Consider the following reaction: A(g)⇌2B(g). Find the equilibrium partial pressures of A and B for each of the following differe
Illusion [34]

Answer:

a. Kp=1.4

P_{A}=0.2215 atm

P_{B}=0.556 atm

b.Kp=2.0 * 10^-4

P_{A}=0.495atm

P_{B}=0.00995 atm

c.Kp=2.0 * 10^5

P_{A}=5*10^{-6}atm

P_{B}=0.9999 atm

Explanation:

For the reaction  

A(g)⇌2B(g)

Kp is defined as:

Kp=\frac{(P_{B})^{2}}{P_{A}}

The conditions in the system are:

          A                    B

initial   0                1 atm

equilibrium x       1atm-2x

At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.    

Replacing these values in the expression for Kp we get:

Kp=\frac{(1-2x)^{2}}{x}

Working with this equation:

x*Kp=(1-2x)^{2} - -> x*Kp=4x^{2}-4x+1- - >4x^{2}-(4+Kp)*x+1=0

This last expression is quadratic expression with a=4, b=-(4+Kp) and c=1

The general expression to solve these kinds of equations is:

x=\frac{-b(+-)*\sqrt{(b^{2}-4ac)}}{2a} (equation 1)

We just take the positive values from the solution since negative partial pressures don´t make physical sense.

Kp = 1.4

x_{1}=\frac{(1.4+4)+\sqrt{(-(1.4+4)^{2}-4*4*1)}}{2*4}=1.128

x_{1}=\frac{(1.4+4)-\sqrt{(-(1.4+4)^{2}-4*4*1)}}{2*4}=0.2215

With x1 we get a partial pressure of:

P_{A}=1.128 atm

P_{B}=1-2*1.128 = -1.256 atm

Since negative partial pressure don´t make physical sense x1 is not the solution for the system.

With x2 we get:

P_{A}=0.2215 atm

P_{B}=1-2*0.2215 = 0.556 atm

These partial pressures make sense so x2 is the solution for the equation.

We follow the same analysis for the other values of Kp.

Kp=2*10^-4

X1=0.505

X2=0.495

With x1

P_{A}=0.505atm

P_{B}=1-2*0.505 = -0.01005 atm

Not sense.

With x2

P_{A}=0.495atm

P_{B}=1-2*0.495 = 0.00995 atm

X2 is the solution for this equation.  

Kp=2*10^5

X1=50001

X2=5*10^{-6}

With x1

P_{A}=50001atm

P_{B}=1-2*50001=-100001atm

Not sense.

With x2

P_{A}= 5*10^{-6}atm

P_{B}=1-2*5*10^{-6}= 0.9999 atm

X2 is the solution for this equation.  

8 0
3 years ago
PLZ HELP!<br><br><br>How does changing the angle of a ramp affect the force required?
galina1969 [7]

Answer:

depending on how you change the angle on the ramp the kanetic energy can go up or down depending on how u angle the ramp

Explanation:

7 0
3 years ago
Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are
sertanlavr [38]

Answer:

Reaction A and B are unfavorable.

Explanation:

Gibbs free energy is an energy which that can be use to convert into useful work.

ΔG°=ΔH°-TΔS°

ΔG°= Gibbs free energy

ΔH° =  enthalpy of reaction

T = temperature of eh reaction

ΔS° = Entropy change

  • If the Gibbs  free energy of the reaction is positive than the reaction will be non spontaneous and the chemical reaction will be not feasible.
  • If the Gibbs  free energy of the reaction is negative than the reaction will be spontaneous and the chemical reaction will be feasible .

According to given information in the question:

Reaction A and B are non spontaneous as their Gibbs free energy value is positive.hence both are unfavorable.

3 0
3 years ago
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