C) They each form similar compounds when combined with oxygen.
Explanation:
The given elements have a common characteristics as they each form similar compounds when combined with oxygen.
Beryllium, magnesium and calcium all are located in the alkaline earth group.
Elements in the same group have the same chemical properties.
- Density and melting point are physical properties of matter which varies down a group on the periodic table.
- Their reaction with oxygen denotes a statement of their chemical properties.
- Chemical properties of matter is a function of their valency.
- Group two elements have a valency of two. They have two electrons in their outermost shell.
- Therefore, they all form ionic bonds when they react with oxygen.
learn more:
Periodic table brainly.com/question/2690837
#learnwithBrainly
Answer:

Explanation:
Hello,
In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

Besr regards.
Answer:
Astatine: Halogen
Nitrogen: Non-Metal
Krypton: Non-Metal, Noble Gas
Chlorine: Non-Metal
Sulfur: Non-metal
Explanation:
Answer:
0.4 M
Explanation:
Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.
Because there's no O₂ in the beginning, the NO will decompose:
N₂(g) + O₂(g) ⇄ 2NO(g)
0.30 0 0.70 Initial
+x +x -2x Reacts (the stoichiometry is 1:1:2)
0.30+x x 0.70-2x Equilibrium
The equilibrium concentrations are the number of moles divided by the volume (0.250 L):
[N₂] = (0.30 + x)/0.250
[O₂] = x/0.25
[NO] = (0.70 - 2x)/0.250
K = [NO]²/([N₂]*[O₂])
K = 
7.70 = (0.70-2x)²/[(0.30+x)*x]
7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)
4x² - 2.80x + 0.49 = 2.31x + 7.70x²
3.7x² + 5.11x - 0.49 = 0
Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70
x = 0.09 mol
Thus,
[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M