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Levart [38]
3 years ago
5

Which best explains why a scientist would share these details in a conference?

Chemistry
1 answer:
kati45 [8]3 years ago
8 0

The question is incomplete, the complete question is; During a conference presentation, a scientist described the materials that she used and how she performed her experiments.

Which best explains why a scientist would share these details in a conference?

It tells the audience if the results support or contradict the hypothesis.

It tells the peers if the study is supported by mathematical models.

It informs the peers if the results are supported by other scientists.

It informs the audience if the study included controlled tests.

Answer:

It informs the audience if the study included controlled tests.

Explanation:

Usually, scientific conferences involve presentation of papers by scientists. These paper presentations are actually the sharing of details of the scientific research carried out by other scientists.

Presenting the materials and methods section of the a research project  to a scientific conference informs the audience if the study included controlled tests.

The inclusion of controlled tests in a scientific study enhances the validity of the results obtained in the study.

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Which type of rock forms as a result of cooling and crystallization?
Dovator [93]

Answer:

Igneous rock is the type of rock that forms as a result of cooling an crystallization

Explanation:

  • Rocks are either sedimentary, igneous or metamorphic based on the chemical composition and the mode of formation.
  • Igneous rocks are formed as a result of the cooling and crystallization of magma from volcanic eruptions.
  • Igneous rocks are either intrusive, which form deep in the crust or extrusive which form on the surface of the earth.
  • Sedimentary rocks are formed as a result of deposition, and cementation of sediments.
  • Metamorphic rocks, on the other hand, are formed from the sedimentary and igneous rocks during the rock cycle.

7 0
3 years ago
Which of these relationships is true of an uncharged atom?
marusya05 [52]

Answer:

The correct option is  C) The number of protons is equal to the number of electrons.

Explanation:

Atoms are made up of particles called protons, neutrons, and electrons. Protons and neutrons are in the center of the atom and form the nucleus, while electrons surround the nucleus. Electrons have a negative charge. The charge of the protons is positive and finally, the neutrons have no charge.

If the atom has no charge, this means that the total charge of the atomic nucleus, which is positive due to the presence of the protons, is equal to the negative charge of the electrons, so that it cancels out.

So, <u><em>the correct option is  C) The number of protons is equal to the number of electrons.</em></u>

7 0
3 years ago
Aluminum, iron, copper, and oxygen are all examples of which of the following
ivolga24 [154]
The answer is elements.

7 0
3 years ago
Please help me solve this!
yulyashka [42]

Answer : The image is attached below.

Explanation :

For O_3:

Molar mass, M = 48 g/mol

Mass, m = 24 g

Moles, n = \frac{m}{M}=\frac{24g}{48g/mol}=0.5mol

Number of particles, N = n\times 6.022\times 10^{23}=0.5\times 6.022\times 10^{23}=3.0\times 10^{23}

For NH_3:

Molar mass, M = 17 g/mol

Mass, m = 170 g

Moles, n = \frac{m}{M}=\frac{170g}{17g/mol}=10mol

Number of particles, N = n\times 6.022\times 10^{23}=10\times 6.022\times 10^{23}=6.0\times 10^{24}

For F_2:

Molar mass, M = 38 g/mol

Mass, m = 38 g

Moles, n = \frac{m}{M}=\frac{38g}{38g/mol}=1mol

Number of particles, N = n\times 6.022\times 10^{23}=1\times 6.022\times 10^{23}=6.0\times 10^{23}

For CO_2:

Molar mass, M = 44 g/mol

Moles, n = 0.10 mol

Mass, m = n\times M=0.10mol\times 44g/mol=4.4g

Number of particles, N = n\times 6.022\times 10^{23}=0.10\times 6.022\times 10^{23}=6.0\times 10^{22}

For NO_2:

Molar mass, M = 46 g/mol

Moles, n = 0.20 mol

Mass, m = n\times M=0.20mol\times 46g/mol=9.2g

Number of particles, N = n\times 6.022\times 10^{23}=0.20\times 6.022\times 10^{23}=1.2\times 10^{23}

For Ne:

Molar mass, M = 20 g/mol

Number of particles = 1.5\times 10^{23}

Moles, n = \frac{N}{6.022\times 10^{23}}=\frac{1.5\times 10^{23}}{6.022\times 10^{23}}=0.25mol

Mass, m = n\times M=0.25mol\times 20g/mol=5g

For N_2O:

Molar mass, M = 44 g/mol

Number of particles = 1.2\times 10^{24}

Moles, n = \frac{N}{6.022\times 10^{23}}=\frac{1.2\times 10^{24}}{6.022\times 10^{23}}=1.9mol

Mass, m = n\times M=1.9mol\times 44g/mol=83.6g

For unknown substance:

Number of particles = 3.0\times 10^{23}

Mass, m = 8.5 g

Moles, n = \frac{N}{6.022\times 10^{23}}=\frac{3.0\times 10^{23}}{6.022\times 10^{23}}=0.50mol

Molar mass, M = \frac{m}{n}=\frac{8.5g}{0.50mol}=17g/mol

The substance is NH_3.

3 0
3 years ago
a gas measured a volume 100 mL under pressure of 740 mmHg. What would the volume be under a pressure of 780 mmHg with constant t
nikdorinn [45]

Answer:

<h2>94.87 mL</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we're finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

We have

V_2 =  \frac{100 \times 740}{780}  =  \frac{74000}{780}  \\  = 94.8717...

We have the final answer as

<h3>94.87 mL</h3>

Hope this helps you

7 0
3 years ago
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