All categories

2 years ago

Can someone plz explain to me how to calculate volume

Mathematics

1 answer:

Vinil7 [7]2 years ago

4 0

Answer:

Length x Width x Height

You might be interested in

Answer each of the questions for the following diagram:

sweet [91]

Answer:

1. Complimentary angles

2. 3x+20 = 10x-15: x = 5

3. I'm not sure on part 3, sorry.

5 0

2 years ago

Find the diagonal of the rectangular solid with the given measures.

Vikki [24]

Answer:

Step-by-step explanation:

Diagonal = $\sqrt{2^{2} +3^{2}+6^{2} } =\sqrt{49} =7$

6 0

2 years ago

1.2 x + 4.6 > 54.6 − 0.8 x

Sedbober [7]

Answer:

look the photo

Step-by-step explanation:

..0000000000000000

3 0

2 years ago

Read 2 more answers

Janine inflated a ball to a radius of 18cm and another ball to a radius of 12cm. How much greater was the volume of the air in t

bagirrra123 [75]

Answer:

17,182.08 cm³

Step-by-step explanation:

6 0

2 years ago

3. A company with loud machinery needs to cut its sound intensity to 44% of its original level. By how many decibels would the l

sergeinik [125]

Answer: <em>3. The correct option is: A) 3.57 decibels.</em>

<em>6. The correct option is: B) $ln(\frac{x^2}{c^5})$ </em>

Step-by-step explanation:

3. Sound intensity is cut to 44% of its original level. That means, if the original sound intensity was 100, then now sound intensity will be 44.

So, $I_{0}= 100$ and $I= 44$

Using the formula $L= 10log(\frac{I}{I_{0}})$ , we will get.....

$L= 10log(\frac{44}{100})\\ \\ L= 10log(0.44)\\ \\ L= 10(-0.3565...)=-3.565...\approx -3.57$

<em>(Rounded to the nearest hundredth)</em>

So, the loudness would be reduced by 3.57 decibels.

6. Given expression is: $2ln(x) - 5ln(c)$

First applying the property $m*log(x)= log(x^m)$ , we will get.....

$ln(x^2)-ln(c^5)$

Now using the formula, $log(a)-log(b)= log(\frac{a}{b})$ , we will get....

$ln(x^2)-ln(c^5) = ln(\frac{x^2}{c^5})$

Thus, the answer as a single natural logarithm is $ln(\frac{x^2}{c^5})$

8 0

2 years ago