D. The terminal point of vector c u lies in quadrant II.
I think the 4th one but Im not too sure please forgive me if I'm wrong.
Slope is 7/3 and y intercept is -3.
45.10 is greater than 45.01
Answer:
Step-by-step explanation:
(3,1) lies below the vertex, so the parabola opens downwards.
Equation for a down-opening parabola with vertex (2,3):
y = a(x-2)² + 3, a<0
Plug in (3,1) and solve for a:
1 = a1² + 3
a = -2
y = -2(x-2)² + 3
