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lisabon 2012 [21]

3 years ago

15

How do you choose between mean and median as the best measure for the center of a distribution

1 answer:

slava [35]3 years ago

8 0

The mean is often the default measure of center because it includes every data point, ie its more representative. However, if you have outliers then the mean will be skewed toward the outlier. For example, with home prices, very expensive houses will make the mean larger than it should be if you focused on the main cluster of data. This is why the median home price is often measured and reported (rather than the mean home price).

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Is domain of f(x,y) = 1 + (4 -y^2)^1/2 open, closed or neither<br><br> is it bounded or unbounded?

omeli [17]

Answer:

Closed and Bounded.

Step-by-step explanation:

Hi there!

1) Let's start by finding the values in which the function is defined. Remember that this can be rewritten:

$f(x,y) = 1 + (4 -y^2)^{\frac{1}{2}} \:id\:est\:f(x,y)=1+\sqrt{(4 -y^2)}$

Since every quadratic root are defined for values $\geq$ 0 then, this help us to understand that we need calculate what interval this Domain is:

$4-y^{2} \geq 0\\4-y^{2}-4\geq -4\\-y^{2}\geq-4 \\y^{2}\leq4\\-2\leq y\leq 2$

$D=[-2,2]$

2) Graphically speaking, the domain is closed. For the values -2 and 2 are included, and bounded.

Bounded functions have all of their points contained by some circle origin centered. Check it out below.

6 0

4 years ago

xeze [42]

Answer:

d

Step-by-step explanation:

always d

3 0

3 years ago

paden payes $2.10 for 5 1/2 pounds of bananas. Alyssa pays $3.25 for 6 1/2 of bananas. Which is the better buy

Kazeer [188]

$2.10 for 5 1/2 lbs.

4 0

3 years ago

Moosa's sister is six years younger than 3 times his age. The sum of their ages is 30. How old is Moosa?

elena55 [62]

Suppose Moosa is ( x ) years old ,

Thus Moosa's sister is ( 3x - 6 ) years old .

The sum of their ages is 30 :

( x ) + ( 3x - 6 ) = 30 ==》 4x - 6 = 30

==》 4x = 36

==》 x = 9

So Moosa is 9 years old .

8 0

3 years ago

A random variable x is uniformly distributed over the interval (-4, 6). Find the standard deviation of x. (Note: Uniform distrib

Pachacha [2.7K]

Answer:

The standard deviation of x is 2.8867

Step-by-step explanation:

The standard deviation of variable x that follows a uniform distribution is calculated as:

$s = \sqrt{\frac{(b-a)^{2} }{12} }$

Where (a,b) is the interval where x is defined.

So, replacing a by -4 and b by 6, the standard deviation is:

$s = \sqrt{\frac{(6-(-4))^{2} }{12} }$

$s = \sqrt{\frac{(10)^{2} }{12} }$

$s=\sqrt{\frac{100}{12} }$

$s=\sqrt{8.3333}$

$s=2.8867$

3 0

4 years ago