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3 years ago

A sample of water is mixed with a surfactant. What will most likely happen to the viscosity of the water? Explain your answer.

2 answers:

4 0

Surfactants disrupt intermolecular forces inside liquids and viscosity is directly related to intermolecular forces so, if intermolecular forces are decreased, viscosity should decrease as well.

BaLLatris [955]3 years ago

3 0

Answer:

The viscosity of the water will decrease.

Surfactants disrupt intermolecular forces within a liquid.

Viscosity is directly related to intermolecular forces.

If intermolecular forces are decreased, viscosity should also decrease.

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Question (ii) answer

katrin [286]

The student stirs it because he wants the reaction to take place more quickly.

4 0

3 years ago

The characteristic which distinguishes a true solid from other phases of matter at STP is that in a true solid the particles are

Harlamova29_29 [7]

Answer:

Background

Solids – relatively rigid, definite volume and shape. In a solid, the atoms and molecules are attached to each other. ...

Liquids – definite volume but able to change shape by flowing. In a liquid, the atoms and molecules are loosely bonded. ...

Gases – no definite volume or shape

8 0

2 years ago

A student is given an antacid tablet that weighed 5.6832 g. The tablet was crushed and 4.3628 g of he antacid was added to 200 m

SSSSS [86.1K]

Answer:

a) 8.33 ml of the original stomach acid is neutralized

b) 191.67 ml of the stomach acid was neutralized

c) 249.68 ml acid would be neutralized by the original tablet

Explanation:

a) how much of the stomach acid had been neutralized in the 25 mL sample wich was titrated?

25.5 ml of a NaOH solution is equivalent to 25.00 ml of the original stomach acid

8.5 ml NaOH * (25.00 ml original stomach acid / 25.5 ml NaOH) = 8.33 ml original stomach acid

b) how much stomach acid was neutralized y the 4.3628 g tablet?

It takes 8.5 ml NaOH to neutralize 8.33 ml original acid (this is the answer for question 1)

This means the antacid neutralized = 200 ml - 8.33 ml = 191.67 ml

c) how much stomach acid would have been neutralized by the original 5.6832 g tablet

4.3628 g antacid is equivalent to 191.67 ml acid ( this is the answer for question 2)

5.6832g antacid * (191.67 ml acid / 4.3628 g antacid) = 249.68 ml acid

3 0

3 years ago

Read 2 more answers

For the reaction, A(g) + B(g) => AB(g), the rate is 0.385 mol/L.s when the initial concentrations of both A and B are 2.00 mo

Tanya [424]

Answer : The rate for a reaction will be $0.14Ms^{-1}$

Explanation :

The balanced equations will be:

$A(g)+B(g)\rightarrow AB(g)$

In this reaction, $A$ and $B$ are the reactants.

The rate law expression for the reaction is:

$\text{Rate}=k[A]^2[B]^1$

or,

$\text{Rate}=k[A]^2[B]$

Now, calculating the value of 'k' by using any expression.

$\text{Rate}=k[A]^2[B]$

$0.385=k(2.00)^2(2.00)$

$k=0.0481M^{-2}s^{-1}$

Now we have to calculate the initial rate for a reaction that starts with 1.48 M of reagent A and 1.32 M of reagents B.

$\text{Rate}=k[A]^2[B]^0[C]^1$

$\text{Rate}=(0.0481)\times (1.48)^2(1.32)^1$

$\text{Rate}=0.14Ms^{-1}$

Therefore, the rate for a reaction will be $0.14Ms^{-1}$

7 0

4 years ago

You titration 5.0 mL of HCl with 0.010 M NaOH. You find the end point of your titration occurs when 12.0 mL of NaOH has been add

Nookie1986 [14]

your answer is 0.00833M the volume was converted into liters

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Using the molarity equation, we can find the number of moles of HCl that reacted:

molarity=mol soluteL soln

mol solute=(molarity)(L soln)

mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl

(volume converted to liters)

Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:

0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH

Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:

molarity=mol soluteL soln

5 0

3 years ago