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Leto [7]
3 years ago
8

If the heating curve is reversed, what describes the melting point?

Chemistry
1 answer:
olasank [31]3 years ago
6 0
The point of Condensation
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Does it take more or less energy to break the weak acid bond or the weak base bond? (compare δh wa, δh wb)? are the reactions en
olya-2409 [2.1K]
Both weak acids and bases based on their name are weak not only based on the amount of materials that can eventually ionize or move into solution.

It would take more energy to remove the bonding electrons in a weak acid or base than compared to a strong Acid or base, thus in part has to do with the overlap of bonding orbitals between the atoms in the chemical bonds.

The values for H would be positive for both indicating an endothermic process, I believe.
4 0
3 years ago
if you make a solution by dissolving 1.0 mol of Fecl3 into 1 kg of water how would the osmotic pressure of this solution compare
sukhopar [10]
Thus the FeCl3 will form 3 Cl- ions and 1 Fe3+ ion. So the molarity of ions of FeCl3 is 4 times than glucose. So according to the calculation formula, the osmotic of FeCl3 is 4 times of glucose.
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4 years ago
Draw the structures of methyl oleate and propylene glycol. Which one is more polar, and how can you tell
Afina-wow [57]

1234567891011121314151617181920

5 0
3 years ago
Please help! Due today. Look at the image:<br> Reuploaded
kirza4 [7]

Answer:

3

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8 0
3 years ago
Calculate the mass (in grams) of methylene bluecrystals that you must weigh in order to make 100.0mL of 1.25 × 10-5mol/L methyle
mario62 [17]

<u>Answer:</u> The mass of methylene blue that must be weighed is 3.99\times 10^{-4}g

<u>Explanation:</u>

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 1.25\times 10^{-5}M

Molar mass of methylene blue = 319.85 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

1.25\times 10^{-5}M=\frac{\text{Mass of methylene blue}\times 1000}{319.85\times 100.0}\\\\\text{Mass of methylene blue}=\frac{1.25\times 10^{-5}\times 319.85\times 100.0}{1000}=3.99\times 10^{-4}g

Hence, the mass of methylene blue that must be weighed is 3.99\times 10^{-4}g

4 0
3 years ago
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