Ask question

Ask question

All categories

Arte-miy333 [17]

2 years ago

12

What is infrared energy? simplify it

2 answers:

alex41 [277]2 years ago

7 0

Infrared energy is the energy of light between microwave radiation and Ultraviolet radiation

sweet-ann [11.9K]2 years ago

3 0

Answer:

It is a type of radiant energy that's invisible to human eyes but that we can feel as heat.

You might be interested in

Gallium (III) carbonate formula

Alex17521 [72]

Ga2(CO3)3 is the formula.

4 0

3 years ago

Which one is it ????

lianna [129]

Cells can generate from non living matter is the answer

3 0

3 years ago

In a molecule of methane, carbon having four valence electrons binds to four hydrogen atoms how many lone pairs of electrons wil

xenn [34]

None. To bind with an hydrogem atom, the carbon needs to ''share'' one of it's valence electron's with the hydrogen's valence electron. Therefore, forming 4 bounds means the carbon atom will share it's 4 valence electrons and there will be no lone electrons.
Read more on Brainly.com - brainly.com/question/1075300#readmore

4 0

3 years ago

2. How have observations of the natural world helped<br> in the development of calendars?

nekit [7.7K]

Answer:

just wanted points

Explanation:

i wasted your time srry

7 0

3 years ago

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

3 0

3 years ago