Someone pls help me with this plsss

At East Middle School, there are 585858 left-handed students and 609609609 right-handed students. The numbers of left- and right

lisabon 2012 [21]

Answer: C. Left-handed: 48 Right-handed: 504

E. Left-handed: 30 Right-handed: 315

Step-by-step explanation:

Here is the completed question:

At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed students at West Junior High are proportional to the numbers at East Middle School. Which of the following could be the numbers of left-handed and right-handed students at West Junior High?

A. Left-handed: 42 Right-handed: 483

B. Left-handed: 28 Right-handed: 378

C. Left-handed: 48 Right-handed: 504

D. Left-handed: 56 Right-handed: 560

E. Left-handed: 30 Right-handed: 315

Since it's direct proportion, we have to calculate the constant of proportionality which will simply be:

= 609 / 58 = 10.5

A. Left-handed: 42 Right-handed: 483

Constant = 483/42 = 11.5

Incorrect

B. Left-handed: 28 Right-handed: 378

Constant = 378/28 = 13.5

Incorrect

C. Left-handed: 48 Right-handed: 504

Constant = 504/48 = 10.5

Correct

D. Left-handed: 56 Right-handed: 560

Constant = 560/56 = 10

Incorrect

E. Left-handed: 30 Right-handed: 315

Constant = 315/30 = 10.5

Correct

Therefore, the correct options are C and E.

3 0

3 years ago

Read 2 more answers

What is the solution to this inequality?

ioda

C. we multiply the equation by 3

5 0

3 years ago

Which is the solution set of the inequality 15 y minus 9 less-than 36 y greater-than nine-fifths y less-than nine-fifths y less-

Vaselesa [24]

Answer:

C. y<3

Step-by-step explanation:

We are required to determine the solution set of the inequality

$15y-9$

Step 1: Add 9 to both sides

$15y-9+9$

Step 2: Divide both sides by 15

$15y \div 15$

The solution set of the given inequality is: y<3.

The correct option is C.

4 0

3 years ago

Read 2 more answers

What is the greatest common factor of the following monomials: 12g^5h^4 g^5h^2

muminat

Answer:

g^5h^2

Step-by-step explanation:

12g^5h^4, g^5h^2

This is one way of doing it. Break down every number and every variable into a product of the simplest factors. Then see how many of each factor appear in both monomials.

12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h

g^5h^2 = g * g * g * g * g * h * h

So far you see every single prime factor of each monomial.

Now I will mark the ones that are present in both. Those are the common factors.

12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h

g^5h^2 = g * g * g * g * g * h * h

The greatest common factor is the product of all the factors that appear in both monomials.

GCF = g * g * g * g * g * h * h = g^5h^2

6 0

3 years ago

On a 40 question test students gain 6 points for each correct answer and lose 0.5 points on each incorrect answer. If everyone r

juin [17]

Answer:

$\text{r}=5.5\text{c}-20$

Step-by-step explanation:

GIVEN: On a $40$ question test students gain $6$ points for each correct answer and lose $0.5$ points on each incorrect answer. If everyone required to give an answer to each question.

TO FIND: the formulas that describes how a student's raw score, r, depends on the number of correct answers he or she provided, c.

SOLUTION:

Total number of incorrect questions $=40-\text{c}$

Total marks deducted due to incorrect question $=(40-\text{c})\times0.5=20-0.5\text{c}$

Total correct questions $=\text{c}$

Total marks scored $=6\text{c}$

Total raw marks $\text{r}=\text{total marks gained}-\text{total marks deducted}$

$\text{r}=6\text{c}-(20-0.5\text{c})$

$\text{r}=5.5\text{c}-20$

ormulas that describes how a student's raw score, r, depends on the number of correct answers he or she provided, c is $\text{r}=5.5\text{c}-20$

7 0

3 years ago