Someone pls help me with this plsss

A soccer player uses her head to hit a ball up in the air from a height of 2 meters with an initial vertical velocity of 5 meter

Mandarinka [93]

Answer:1.32 s

Step-by-step explanation:

Given

The initial height of ball H=2 m

Initial velocity u=5 m/s

Height of ball at any instant is given by

$H=-4.9t^2+5t+2$

The ball will hit the ground when h=0

$-4.9t^2+5t+2=0\\4.9t^2-5t-2=0\\t=\dfrac{5\pm\sqrt{25+4(4.9)(2)}}{2\times 4.9}\\t=\dfrac{5\pm\sqrt{64.2}}{9.8}\\t=\dfrac{5+8.01}{9.8}=1.32\ s\quad\text{Neglecting negative value of t}$

3 0

3 years ago

15 Points!!!!! I need help on this :D

nlexa [21]

840 is the answer
i hope i helped!

5 0

3 years ago

Read 2 more answers

How to add -89 and 17 step by step

Debora [2.8K]

Step-by-step explanation: The easiest way to do this and the way I commonly use is to subtract 17 from 89then make it negative as you are making the negative number smaller by adding a smaller number therefore your answer is -72

6 0

3 years ago

3. There are 124 acorns laying on the ground in your yard, it is predicted that the number of acorns will

Gennadij [26K]

Answer:

507,409

Step-by-step explanation:

if every 5 days the number quadruples (x4), and we want to know how many acorns fall after 30 days, we can divide 30 by 5 so we only have to calculate for the amount of time the take to quadruple.

30 ÷ 5 = 6

so we only have to quadruple the acorns 6 times.

if we start off with 124 acorns, this is what it will look like:

Day 0: 124 acorns

Day 5: 124 x 4 = 496 acorns

Day 10: 496 x 4 = 1984 acorns

Day 15: 1984 x 4 = 7936 acorns

etc... until day 30.

Day 30: 507904 acorns

I hope this was helpful :-)

5 0

3 years ago

A person must score in the upper 8% of the population on an IQ test to qualify for membership in MENSA, the international high-I

Cloud [144]

Answer:

A person must get an IQ score of at least 138.885 to qualify.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 115, \sigma = 17$