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Anna007 [38]
3 years ago
9

A total of 384 tickets were sold for the school play. they were either adult tickets or student tickets. The number of student t

ickets sold was two times the number of adult tickets sold. how many adult tickets were sold
Mathematics
2 answers:
olganol [36]3 years ago
8 0
128 because 128 times 2 is 256 children tickets and 256 plus 128 is 384
lisabon 2012 [21]3 years ago
8 0
256 children tickets. 128 times 2 is 256
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4x + 5y = 102<br> 7y + 5y = 126
galina1969 [7]

Answer:

hope you like my question

Step-by-step explanation:

Hi -

What you want to do here is solve the equation by substitution.

To do that, you solve one of the equations for y. then plug that into the other equation so you have an equation with only x as the variable.

1) Solve either equation for y. Lets go with the first one:

4x+5y=102

Subtract 4x from each side:

5y=102-4x

Divide both sides by 5

y=(102-4x)/5

2) Plug this value for y into the other equation we started with:

7x+5y = 126

7x + 5((102-4x)/5) = 126

3) Solve the resulting equation for x.

Since we are multiplying and dividing (102-4x) by 5 the 2 5s cancel each other out

7x + 5((102-4x)/5) = 126

7x + 102 - 4x = 126

Combine the 2 x terms:

3x+102=126

subtract 102 from each side:

3x = 24

Divide both sides by 3:

x=8

Once we have a value for x, we can plug that number into either one of our starting equations to solve for y.

4x + 5y = 102; if x = 8

32+5y = 102

subtract 32 from each side:

5y = 70

Divide both sides by 5:

y = 14

So x = 8 and y = 14.

You can check your work by plugging these numbers both into your 2 initial equations.

4x+5y=102; 4*8+5*14 = 102

7x+5y=126; 7*8 +5*14 = 126

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Taylor will order one t-shirt for each person who attends her family's reunion. The cost is
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Answer:

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Step-by-step explanation:

Since they can only spend a maximum of $600, we can fill that in for c. Now, we can solve the equation for n.

600 = 8n + 40

~Subtract 40 to both sides

560 = 8n

~Divide 8 to both sides

70 = n

Best of Luck!

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You would have a 3 to 10 chance that the first 3 cars are in order


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