The first relation gives two y-values for any given x-value (except x=6).
y² +x = 6 . . . . . is not a function
Answer:
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Step-by-step explanation:
Answer:
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Answer:
1, 9
Step-by-step explanation:
You're looking for the values of x where f(x) = g(x). Find the matching f(x) and g(x) values in the table. The value of x on that line is one of the solutions.