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Anni [7]
3 years ago
6

Find two consecutive integers whose sum is 93. (Show work)

Mathematics
1 answer:
kenny6666 [7]3 years ago
5 0

You are looking for three consecutive integers whose sum is 93. First, divide 93 by 3 and get 31. Go one above 31 and one below. You get 30, 31 and 32 which sum to 93.

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Factor 64v^3 + 192v^2 -56v - 168​
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Hello from MrBillDoesMath!

Answer:

8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )


Discussion:

Given

64v^3 + 192v^2 - 56 v - 168      

Factor 64v^2 from the first two terms. Factor 56 from the last two terms:

64v^2(v+3) - 56(v  + 3)     => factor (v+3) from both terms

(v+3) (64v^2 - 56)             => factor 8 from both terms in the right ()

8(v+3)(8v^2-7)                   => factor 8y^2-7

8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )



Thank you,

MrB

4 0
3 years ago
Devon rented a U Haul truck for $48 for 4 hours plus $13.50 per each hour you go over. At the end of the day, his total bill was
Rasek [7]

Answer:

You need to write an equation to find the answer to this:

h = hours

48 + 13.5h = 112.50               -First you need to subtract 48 from both sides

48 - 48 + 13.5h = 112.50 - 48

13.5h = 64.5         -Now divide both sides by 13.5

13.5h / 13.5 = 64.5 / 13.5

h = 4.77777778

However, I would just round to 5.

I hope this helps!

-Mikayla



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