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Archy [21]
3 years ago
7

Solve the inequality: –3(x + 2) > 4x + 5(x – 7)

Mathematics
1 answer:
Gwar [14]3 years ago
4 0

Answer:

29/12 > x

Step-by-step explanation:

–3(x + 2) > 4x + 5(x – 7)

Distribute

-3x -6 > 4x +5x-35

Combine like terms

-3x-6 > 9x -35

Add 3x to each side

-3x+3x-6 > 9x+3x -35

-6 > 12x-35

Add 35 to each side

-6+35 > 12x -35+35

29 > 12x

Divide each side by 12

29/12 > 12x/12

29/12 > x

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I need help doings this​
julia-pushkina [17]

Answer:

Either A or C, I'm not quite sure tho

Step-by-step explanation:

The line is on the negative side of the graph

6 0
3 years ago
Which of the following intervals represents the set (1,4) u [2,6]?
fenix001 [56]
Set is a sum of two intervals :(1,4) u [2,6] 
In the first interval it is open on both sides so 1 and 4 don't belong to this interval, the second is closed so both 2 and 6 belong to interval and numbers between 2 and 6
We can write it as 1<x\leq 6
summing both sets we have one set: (1,6]
so
a) represent our set
b) also represent because all numbers between 4-6 and 6 are in our set
c)also represent, all numbers are in main set
d)also represent

8 0
3 years ago
Read 2 more answers
Can someone please help me
Ipatiy [6.2K]

Answer:

Y-int:2

Slope: 4

Step-by-step explanation:

Hope this helps!

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7 0
3 years ago
Read 2 more answers
Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A
MAVERICK [17]
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
    = -2cos4A*sin3A + 2cos4A*sinA
    = 2cos4A(sinA - sin3A)
    = 2cos4A*2cos(2A)sin(-A)
    = -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
   = 2cos4A*cos3A - 2cos4A*cosA
   = 2cos4A(cos3A - cosA)
   = 2cos4A*(-2)sin2A*sinA
   = -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
       = cos2A/sin2A
      = cot2A

This verifies the identity.
4 0
3 years ago
A line passes through the points (-3, 14) and (-1, 16). What is its equation in slope-intercept form?​
timurjin [86]

Answer:

y = 6x + 22

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-3, 14)

Point (-1, 16)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{16-14}{-1+3}
  2. Subtract/Add:               m=\frac{12}{2}
  3. Divide:                           m=6

<u>Step 3: Find y-intercept </u><em><u>b</u></em>

  1. Define:                    y = 6x + b
  2. Substitute:              16 = 6(-1) + b
  3. Multiply:                  16 = -6 + b
  4. Isolate <em>b</em>:                 22 = b
  5. Rewrite:                   b = 22

<u>Step 4: Write linear equation</u>

y = 6x + 22

5 0
3 years ago
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