Answer:
Either A or C, I'm not quite sure tho
Step-by-step explanation:
The line is on the negative side of the graph
Set is a sum of two intervals :(1,4) u [2,6]
In the first interval it is open on both sides so 1 and 4 don't belong to this interval, the second is closed so both 2 and 6 belong to interval and numbers between 2 and 6
We can write it as 1<x

summing both sets we have one set: (1,6]
so
a) represent our set
b) also represent because all numbers between 4-6 and 6 are in our set
c)also represent, all numbers are in main set
d)also represent
Answer:
Y-int:2
Slope: 4
Step-by-step explanation:
Hope this helps!
P.S. Stay Safe!
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.
We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)
N = -(sin7A - sinA) + sin5A - sin3A
= -2cos4A*sin3A + 2cos4A*sinA
= 2cos4A(sinA - sin3A)
= 2cos4A*2cos(2A)sin(-A)
= -4cos4A*cos2A*sinA
D = cos7A + cosA - (cos5A + cos3A)
= 2cos4A*cos3A - 2cos4A*cosA
= 2cos4A(cos3A - cosA)
= 2cos4A*(-2)sin2A*sinA
= -4cos4A*sin2A*sinA
Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
= cos2A/sin2A
= cot2A
This verifies the identity.
Answer:
y = 6x + 22
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
Slope Formula: 
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-3, 14)
Point (-1, 16)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:

- Subtract/Add:

- Divide:

<u>Step 3: Find y-intercept </u><em><u>b</u></em>
- Define: y = 6x + b
- Substitute: 16 = 6(-1) + b
- Multiply: 16 = -6 + b
- Isolate <em>b</em>: 22 = b
- Rewrite: b = 22
<u>Step 4: Write linear equation</u>
y = 6x + 22