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Nata [24]
3 years ago
13

How does Newton's 2nd law relate to Moment of Inertia?

Physics
2 answers:
ki77a [65]3 years ago
8 0
When a torque is applied to an object it rotates with acceleration which is inversely proportional to its moment of inertia. The moment of inertia is a rotational mass and the torque is a rotational force
amm18123 years ago
5 0
Inertia and Inertial mass is found out using Newton’s Second law. Newtons second law states: “A larger resultant force acting upon an object, the greater acceleration that object will have, Meaning force and acceleration are directly proportional to each other (f∝a), and acceleration is inversely proportionate to the mass of an object. This is shown through the formula: f = ma, where
f = Force in Newtons, m = Mass in Kilograms, Kg and a = Acceleration in m/s^2

This, therefore, can be arranged to find Mass, or Acceleration, using that acceleration is inversely proportionate to the mass of an object.

Inertia is 'The tendency for motion to remain unchanged', basically the measurement that objects move at the same velocity, or not at all. This links to Newton's first law that until acted upon a resultant force, objects moving and not moving will stay moving at that velocity.
Inertial mass is the measurement for how difficult it is to change the velocity for the object. Using the previous Newtons second law formula: F =ma
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A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.0 ft/s,
natka813 [3]

Answer:

The angle's rate of change is: -0.125 (degree/feet).

Explanation:

In this case of problem we need to find the angle's rate (α) of change when x=6 ft. First we need to relate (α) with x and y and the expression that do it is: \alpha =Arctan(\frac{y}{x}) where (α) is the angle between the ladder and the ground, x is the horizontal distance and y the vertical distance, now we need to have the variable y at function of x, so we can do it using the Pythagorean theorem and gets:y^{2} +x^{2} =10^{2} solving for y(x) we get:y(x)=\sqrt{100-x^{2}}. Replacing all we have got in the first equation: \alpha =Arctan(\frac{\sqrt{100-x^{2} } }{x}). Finally we derivate this equation at function of variable x and gets this result:\frac{d\alpha }{dx} =\frac{-1}{\sqrt{100-x^{2} } } evaluating at x=6 ft we get: -0.125(degree/feet). The negative signal means that the angle is decreasing.

4 0
3 years ago
Read 2 more answers
Josh starts at a position of x=0 meters at the left side of the front of the classroom. Over the course of the class he walks ba
Aneli [31]
Answer:
180 meters

Explanation:
Josh walks 6 meters to the right and the 6 meters back. This means that in one time, Josh walks a total distance of 6+6 = 12 meters
Now, we are given that Josh walks this same distance 15 times.
Therefore, we will multiply this distance by 15 to get the total distance that he walks as follows:
Total distance = 12*15 = 180 meters

Based on the above calculations, Josh walks 180 meters over the course of the class

Hope this helps :)
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Your constantly using your body to move around
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<h3><em><u>Hope it helps you </u></em><em><u>♡</u></em><em><u>♡</u></em></h3>

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Andre45 [30]
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